如何用python dataframe中的某些字符替换列的开头和结尾

我有一个如下所示的数据帧：

 clients_x                 clients_y              coords_x               coords_y 
7110001002                7100019838    -23.63013,-46.704887  -23.657433,-46.744095   
7110001002                7100021875    -23.63013,-46.704887    -23.7729,-46.591366   
7110001002                0700245857    -23.63013,-46.704887      -23.7074,-46.5698 
[7110052941, 7110107795]  7100019838        -23.609,-46.6974  -23.657433,-46.744095
[7110052941, 7110107795]  7100021875        -23.609,-46.6974    -23.7729,-46.591366
[7110052941, 7110107795]  0700245857        -23.609,-46.6974       -23.7074,-46.569

df["clients_x"] = "[" + "df["clients_x"]" + "]"

我要做的是让

clients\u x

列中的所有值以“[]”开头和结尾。因此，我的预期输出是：

 clients_x                 clients_y              coords_x               coords_y 
[7110001002]                7100019838    -23.63013,-46.704887  -23.657433,-46.744095   
[7110001002]                7100021875    -23.63013,-46.704887    -23.7729,-46.591366   
[7110001002]                0700245857    -23.63013,-46.704887      -23.7074,-46.5698 
[7110052941, 7110107795]  7100019838        -23.609,-46.6974  -23.657433,-46.744095
[7110052941, 7110107795]  7100021875        -23.609,-46.6974    -23.7729,-46.591366
[7110052941, 7110107795]  0700245857        -23.609,-46.6974       -23.7074,-46.569

 clients_x                 clients_y              coords_x               coords_y 
[7110001002]                7100019838    -23.63013,-46.704887  -23.657433,-46.744095   
[7110001002]                7100021875    -23.63013,-46.704887    -23.7729,-46.591366   
[7110001002]                0700245857    -23.63013,-46.704887      -23.7074,-46.5698 
[[7110052941, 7110107795]]  7100019838        -23.609,-46.6974  -23.657433,-46.744095
[[7110052941, 7110107795]]  7100021875        -23.609,-46.6974    -23.7729,-46.591366
[[7110052941, 7110107795]]  0700245857        -23.609,-46.6974       -23.7074,-46.569

首先，我试着做这样的事情：

 clients_x                 clients_y              coords_x               coords_y 
7110001002                7100019838    -23.63013,-46.704887  -23.657433,-46.744095   
7110001002                7100021875    -23.63013,-46.704887    -23.7729,-46.591366   
7110001002                0700245857    -23.63013,-46.704887      -23.7074,-46.5698 
[7110052941, 7110107795]  7100019838        -23.609,-46.6974  -23.657433,-46.744095
[7110052941, 7110107795]  7100021875        -23.609,-46.6974    -23.7729,-46.591366
[7110052941, 7110107795]  0700245857        -23.609,-46.6974       -23.7074,-46.569

df["clients_x"] = "[" + "df["clients_x"]" + "]"

但是，这样做实际上会在每个值的开头和结尾添加“[]”，但是对于那些已经有“[]”的行，将复制它们。输出如下：

 clients_x                 clients_y              coords_x               coords_y 
[7110001002]                7100019838    -23.63013,-46.704887  -23.657433,-46.744095   
[7110001002]                7100021875    -23.63013,-46.704887    -23.7729,-46.591366   
[7110001002]                0700245857    -23.63013,-46.704887      -23.7074,-46.5698 
[7110052941, 7110107795]  7100019838        -23.609,-46.6974  -23.657433,-46.744095
[7110052941, 7110107795]  7100021875        -23.609,-46.6974    -23.7729,-46.591366
[7110052941, 7110107795]  0700245857        -23.609,-46.6974       -23.7074,-46.569

 clients_x                 clients_y              coords_x               coords_y 
[7110001002]                7100019838    -23.63013,-46.704887  -23.657433,-46.744095   
[7110001002]                7100021875    -23.63013,-46.704887    -23.7729,-46.591366   
[7110001002]                0700245857    -23.63013,-46.704887      -23.7074,-46.5698 
[[7110052941, 7110107795]]  7100019838        -23.609,-46.6974  -23.657433,-46.744095
[[7110052941, 7110107795]]  7100021875        -23.609,-46.6974    -23.7729,-46.591366
[[7110052941, 7110107795]]  0700245857        -23.609,-46.6974       -23.7074,-46.569

为了避免这个问题，我尝试使用以下代码，基本上我想在

clients\u x

列中以数字开头的每个值的开头和结尾添加“[]”

df['clients_x'] = df['clients_x'].mask(df['clients_x'].astype(str).str.startswith(r'^\d'), f'[{df.clients_x}]')

但是，这行代码生成的输出与我的原始数据帧相同。如果有人知道如何解决这个问题，我将非常感谢您的帮助。

使用-

使用-

输出

0               [7110001002]
1               [7110001002]
2               [7110001002]
3    [7110052941,7110107795]
4    [7110052941,7110107795]
5    [7110052941,7110107795]
Name: clients_x, dtype: object

使用-

使用-

输出

0               [7110001002]
1               [7110001002]
2               [7110001002]
3    [7110052941,7110107795]
4    [7110052941,7110107795]
5    [7110052941,7110107795]
Name: clients_x, dtype: object

---

您需要使用

where

，而不是

mask

（请参阅）：

df[“clients\u x”]=df.clients\u x.where(
df.clients_x.astype（str）.str.startswith（“[”），
“[“+df.clients_x+”]”
)

您需要使用

where

，而不是

mask

（请参阅）：

df[“clients\u x”]=df.clients\u x.where(
df.clients_x.astype（str）.str.startswith（“[”），
“[“+df.clients_x+”]”
)