Python 如何将以下三个列表分为7组？

我试图将A、B和C中的元素分开。我尝试使用if-else，但它似乎有点硬编码

A = ["a","b","c","d"]
B = ["a","c","g","e"]
C = ["a","b","f","e"]
X = [[]*7]
common = set(A+B+C)
common1 = set(A) & set(B) & set(C)
common2 = set(A) & set(B)
common3 = set(A) & set(C)
common4 = set(C) & set(B)
for e in common:
    if e in common1:
        X[0] += e
    elif e in common2:
        X[1] += e
    elif e in common3:
        X[2] += e
    elif e in common4:
        X[3] += e
    elif e in A:
        X[4] += e
    elif e in B:
        X[5] += e
    else:
        X[6] += e



X[0] should contain elements common in A,B,C
X[1] should contain elements common in A,B.
X[2] should contain elements common in A,C.
X[3] should contain elements common in C,B.
X[4] should contain elements common in A.
X[5] should contain elements common in B.
X[6] should contain elements common in C.

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最好在字典中完成吗？

不是很好的代码，但做了您想要的：

from itertools import combinations
from operator import and_
from functools import reduce

A = ["a", "b", "c", "d"]
B = ["a", "c", "g", "e"]
C = ["a", "b", "f", "e"]

lst = (set(A), set(B), set(C))
ret = []
for r in range(3, 0, -1):
    for comb in combinations(lst, r=r):
        ret.append(reduce(and_, comb))
print(ret)

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我把你的列表转换成了集合<代码>集合a和集合b（

分别添加（集合a和集合b）

）选择两个集合中的项目

itertools.combinations

调用

r=3

，

r=2

和

r=1

按您需要的顺序选择组合。

我将使用集合和

set.intersection

：

A = set(["a","b","c","d"])
B = set(["a","c","g","e"])
C = set(["a","b","f","e"])
X = [
    list(A.intersection(B,C)),
    list(A.intersection(B)),
    list(A.intersection(C)),
    list(B.intersection(C)),
    list(A),
    list(B),
    list(C)]

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不像@hiro的代码那样可扩展，但一眼就能看出它在做什么。

看看这里：当询问家庭作业时（1）注意你的学校政策：在这里寻求帮助可能构成作弊。（2） 指定问题是家庭作业。（3） 首先，真诚地尝试自己解决问题（在问题中包含代码）。（4） 询问现有实施中的具体问题；看见还有，是关于问家庭作业问题的指导。@hiro主角你说得对！X=[集合（A）&集合（B）&集合（C），集合（A）&集合（B），集合（A）&集合（C），集合（C）&集合（B），集合（A），集合（B），集合（C）]组合使用得很好@Ruzihm谢谢。另一方面：以奇怪的方式（或数据结构）排列结果。。。