Python 模块无法与pygame一起正常工作

我无法使用主模块中其他模块中的函数

#MAIN FILE - mainfile.py

#Imports / display / pygame.init

from file2 import *

font=pygame.font.SysFont("Arial",35)

example(1) #THERE I DEFINE DE CLASS

Text=font.render(list1[0],0,(255,255,255))
win.blit(Text,(5,5))


#while loop

---

我知道我可以在文件2中定义示例类，但我想在主文件中定义它。在您的示例中，

函数

可能比

类

更好。最好使用

return

，而不是

global

在

file2.py中

def get_list(whichlist)
    if whichlist == 1:
       return ["bird", "bird2", "bird3"]
    elif whichlist == 2:
       return ["bird", "bird2", "bird3"]
    #else:
    #   return []

from file2 import get_list

list1 = get_list(1)

class Example:

    def get_list(self, whichlist):
        if whichlist == 1:
            return ["bird", "bird2", "bird3"]
        elif whichlist == 2:
            return ["bird", "bird2", "bird3"]
        #else:
        #    return []

from file2 import Example

ex = Example()
list1 = ex.get_list(1)

在

file1.py中

def get_list(whichlist)
    if whichlist == 1:
       return ["bird", "bird2", "bird3"]
    elif whichlist == 2:
       return ["bird", "bird2", "bird3"]
    #else:
    #   return []

from file2 import get_list

list1 = get_list(1)

class Example:

    def get_list(self, whichlist):
        if whichlist == 1:
            return ["bird", "bird2", "bird3"]
        elif whichlist == 2:
            return ["bird", "bird2", "bird3"]
        #else:
        #    return []

from file2 import Example

ex = Example()
list1 = ex.get_list(1)

---

若您真的需要使用类，那个么您应该在类中创建使用

return

对类使用

CamelCaseNames

也有一个很好的规则——它的意思是

Example

而不是'Example'

在

file2.py中

def get_list(whichlist)
    if whichlist == 1:
       return ["bird", "bird2", "bird3"]
    elif whichlist == 2:
       return ["bird", "bird2", "bird3"]
    #else:
    #   return []

from file2 import get_list

list1 = get_list(1)

class Example:

    def get_list(self, whichlist):
        if whichlist == 1:
            return ["bird", "bird2", "bird3"]
        elif whichlist == 2:
            return ["bird", "bird2", "bird3"]
        #else:
        #    return []

from file2 import Example

ex = Example()
list1 = ex.get_list(1)

在

file1.py中

def get_list(whichlist)
    if whichlist == 1:
       return ["bird", "bird2", "bird3"]
    elif whichlist == 2:
       return ["bird", "bird2", "bird3"]
    #else:
    #   return []

from file2 import get_list

list1 = get_list(1)

class Example:

    def get_list(self, whichlist):
        if whichlist == 1:
            return ["bird", "bird2", "bird3"]
        elif whichlist == 2:
            return ["bird", "bird2", "bird3"]
        #else:
        #    return []

from file2 import Example

ex = Example()
list1 = ex.get_list(1)

最终

list1 = Example().get_list(1)

---

仅仅把它放在那里到底有什么问题？我如何在主文件中定义类而不产生错误，我正在讨论示例（1）您能否详细解释“错误”是什么？要在文件1中定义，您必须将代码从文件2复制到文件2。但可能您的意思是“如何使用来自其他文件的类”。但在您的示例中，

函数

似乎比

类

更好。