如何在Python中水平打印字典中的列表？

你好，我正在制作一个ASCII横幅，它要么打印一个列表字典，形成一个星号字母表。到目前为止，我成功地垂直打印了它，但水平打印时遇到了问题

有人能帮我吗

这就是我目前所拥有的

我水平打印的方法是串联分配，它打印列表的所有第一个元素，然后打印第二个元素

但似乎我的逻辑是有缺陷的，因为当我把它放在一个嵌套的循环中时，它连到了第一行

letter_dict = {'A':
["***** ",
"*   * ",
"***** ",
"*   * ",
"*   * "],
'B':["***   ",
     "*   * ",
     "****  ",
     "*   * ",
     "****  "],
'C':["***** ",
     "*     ",
     "*     ",
     "*     ",
     "***** "],
'D':["****  ",
     "*   * ",
     "*   * ",
     "*   * ",
     "****  "],
'E':["***** ",
     "*     ",
     "***** ",
     "*     ",
     "***** "],
'F':["***** ",
     "*     ",
     "***** ",
     "*     ",
     "*     "],
'G':["***** ",
     "*     ",
     "* *** ",
     "* * * ",
     "***** "],
'H':["*     ",
     "*     ",
     "***** ",
     "*     ",
     "*     "],
'I':["***** ",
     "  *   ",
     "  *   ",
     "  *   ",
     "***** "],
'J':["***** ",
     "  *   ",
     "  *   ",
     "  *   ",
     "***   "],
'K':["*   * ",
     "*  *  ",
     "* *   ",
     "*  *  ",
     "*   * "],
'L':["*     ",
     "*     ",
     "*     ",
     "*     ",
     "***** "],
'M':["*   * ",
     "* * * ",
     "*   * ",
     "*   * ",
     "*   * "],
'N':["*     ",
     "**    ",
     "* *   ",
     "*  *  ",
     "*   * "],
'O':["***** ",
     "*   * ",
     "*   * ",
     "*   * ",
     "***** "],
'P':["***** ",
     "*   * ",
     "***** ",
     "*     ",
     "*     "],
'O':["***** ",
     "*   * ",
     "*   * ",
     "* **  ",
     "*** * "],
'R':["***** ",
     "*   * ",
     "***** ",
     "*  *  ",
     "*   * "],
'S':["***** ",
     "*     ",
     "***** ",
     "    * ",
     "***** "],
'T':["***** ",
     "  *   ",
     "  *   ",
     "  *   ",
     "  *   "],
'U':["*   * ",
     "*   * ",
     "*   * ",
     "*   * ",
     "***** "],
'V':["*   * ",
     "*   * ",
     "*   * ",
     " * *  ",
     "  *   "],
'W':["*   * ",
     "*   * ",
     "*   * ",
     "* * * ",
     " * *  "],
'X':["*   * ",
     " * *  ",
     "  *   ",
     " * *  ",
     "*   * "],
'X':["*   * ",
     " * *  ",
     "  *   ",
     "  *   ",
     "  *   "],
'Z':["***** ",
     "   *  ",
     "  *   ",
     " *    ",
     "***** "]}


def print_banner(str_input, horizontal):

    str_input = str_input.upper()

    if horizontal != True:
        for i in range(len(str_input)):
            for j in range(6):
                print(letter_dict[str_input[i]][j])

    else:
        horizontal_line = ""


        for m in range(len(str_input)):

            horizontal_line += letter_dict[str_input[m]][0]

        print(horizontal_line)

print_banner("ABCD", True)

---

嗯。你需要像点阵式打印机一样，一行一行地合成整个图像：

else:
     for line in range(5):               # Each letter is 5 lines high
          for m in str_input:           
               horizontal_line += letter_dict[m][line]
          horizontal_line += "\n"
     print(horizontal_line)

运行示例：

In [7]: str_input = "BAR"

In [8]: horizontal_line = ""

In [9]: %paste
     for line in range(5):               # Each letter is 5 lines high
          for m in str_input:
               horizontal_line += letter_dict[m][line]
          horizontal_line += "\n"
     print(horizontal_line)

***   ***** *****
*   * *   * *   *
****  ***** *****
*   * *   * *  *
****  *   * *   *

---

您可以使用

zip

使操作更干净：

for line in zip(letter_dict['L'],letter_dict['O'],letter_dict['L']):
    print(*line)

*      *****  *     
*      *   *  *     
*      *   *  *     
*      *   *  *     
*****  *****  ***** 

---

请注意，您在上面的

字母dict

中有一个错误，您在“O”中指定了“Q”。我相信您的“H”格式不正确。

如果您使用的是Unix/Linux，为什么不使用“banner”调用呢？我尝试了您的解决方案，它与我的初始代码有相同的问题。在嵌套循环中，第一行的ascii列表迭代5次，然后第二行迭代5次。或者至少我认为这就是我所要做的，我也做得很好。我忽略了水平线+=“\n”。你能给我解释一下那是什么吗？