Python 如何从一个类发出Qtsignal,从而在pyqt中从其父类发出Qtsignal
我有一个要求,我的执行将发生在线程中,我希望从该线程向主类发出信号。下面是我的示例代码片段,我在其中创建了Python 如何从一个类发出Qtsignal,从而在pyqt中从其父类发出Qtsignal,python,multithreading,qt,pyqt,pyqt4,Python,Multithreading,Qt,Pyqt,Pyqt4,我有一个要求,我的执行将发生在线程中,我希望从该线程向主类发出信号。下面是我的示例代码片段,我在其中创建了MainClass的一个实例,并将其分配给temp。其中,MainClass内部连接到一个线程Thread1,实际工作将在该线程中进行。当信号从Thread1发出时,我希望执行从temp 代码片段 class Thread1(QtCore.QThread): ThreadSignal = QtCore.pyqtSignal(str) While True:
MainClass
的一个实例,并将其分配给temp
。其中,MainClass
内部连接到一个线程Thread1
,实际工作将在该线程中进行。当信号从Thread1
发出时,我希望执行从temp
代码片段
class Thread1(QtCore.QThread):
ThreadSignal = QtCore.pyqtSignal(str)
While True:
#some statments
if Condition:
ThreadSignal.emit('Yes')
else:
ThreadSignal.emit('No')
class MainClass(QtCore.QObject):
MainSignal = QtCore.pyqtSignal(str)
Testinstance = Thread1()
def signalcalled(s):
print s
if __name__=='__main__':
app = AtGui.QApplication(sys.argv)
temp = MainClass()
temp.MainSignal.connect(signalcalled)
sys.exit(app.exec()_)
这应该起作用:
#!/usr/bin/env python
#-*- coding:utf-8 -*-
from PyQt4 import QtCore, QtGui
class myThread(QtCore.QThread):
threadSignal = QtCore.pyqtSignal(str)
def __init__(self, parent=None):
super(myThread, self).__init__(parent)
def run(self):
while True:
if True:
self.threadSignal.emit('Yes')
else:
self.threadSignal.emit('No')
break
class myMainClass(QtCore.QObject):
mainSignal = QtCore.pyqtSignal(str)
def __init__(self, parent=None):
super(myMainClass, self).__init__(parent)
testInstance = myThread(self)
testInstance.threadSignal.connect(self.mainSignal.emit)
testInstance.start()
def signalcalled(s):
print s
if __name__ == "__main__":
import sys
app = QtGui.QApplication(sys.argv)
main = myMainClass()
main.mainSignal.connect(signalcalled)
sys.exit(app.exec_())
您是否尝试过
thread1.ThreadSignal.connect(self.MainSignal.emit)
?@Blender,如果我使用thread1.ThreadSignal.connect(self.MainSignal.emit)
然后,如果我有两个MainClass
实例,并且每个实例都必须在发出Thread1
信号时运行不同的def,则会出现问题Testinstance
是类变量还是实例变量?@BlenderTestinstance
是Thread1
类的实例MainClass
得到了解决方案,您的应用程序正在运行。另一个解决方法是将线程信号连接到主信号。我们可以使用“testInstance.threadSignal.connect(self.mainSignal.emit)”而不是“testInstance.threadSignal.connect(self.mainSignal)”,而不使用emit,它也可以工作。thx的帮助+1
class Thread1(QtCore.QThread):
ThreadSignal = QtCore.pyqtSignal(str)
def __init__(self):
super(myThread, self).__init__()
def run(self):
While True:
#some statments
if Condition:
ThreadSignal.emit('Yes')
else:
ThreadSignal.emit('No')
class MainClass(QtCore.QObject):
MainSignal = QtCore.pyqtSignal(str)
def __init__(self):
super(myThread, self).__init__()
Testinstance = Thread1()
Testinstance.ThreadSignal.connect(MainSignal)
Testinstance.start()
def signalcalled(s):
print s
if __name__=='__main__':
app = AtGui.QApplication(sys.argv)
temp = MainClass()
temp.MainSignal.connect(signalcalled)
sys.exit(app.exec()_)