python：使用正则表达式查找特定单词

这是我的字符串：

您在xxxx银行“借记/贷记/存款/…”上的“1897.00卢比”的“xxxx”处交易的一次性密码，以“0000”结尾的卡为“0000”

xxxx

-字符串，

0000

-数字

我要获取单引号（'）中的所有值

这就是我尝试过的：

[a-z]+，（[a-z]+）[a-z]+（[0-9\.]+）

直到这里它是正确的

现在我想取（借/贷/…），我正在做：

在你的

[a-z]+

银行

[a-z]+[a-z]+（[0-9]+）[a-z]+[0-9]

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更好的方法是什么？

您要查找的正则表达式只是

r“（.*？”

。下面是一个示例程序：

import re

regex = r"'(.*?)'"

test_str = "\"one time password for your transaction at, 'xxxx' of inr '1897.00' on your xxxx bank 'debit/credit/deposit/....' card ending '0000' is 0000\""

matches = re.finditer(regex, test_str)

for matchNum, match in enumerate(matches):
    print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))

哪些产出：

Match 0 was found at 44-50: 'xxxx'
Match 1 was found at 58-67: '1897.00'
Match 2 was found at 86-113: 'debit/credit/deposit/....'
Match 3 was found at 126-132: '0000'

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在此处了解有关使用正则表达式的更多信息：

如果希望单引号中的所有字符

import re
string = "'xxxx' of inr '1897.00' on your xxxx bank 'debit/credit/deposit/....' card ending '0000' is 0000"
all_matches = re.findall(r"\'.+?\'",string)
print all_matches

---

最安全、最有效的方法是匹配两个单引号之间不是单引号的任何内容（在这种情况下贪婪或懒惰无关紧要）：

代码示例：

import re    
regex = r"'[^']*'"    
test_str = '''one time password for your transaction at, 'xxxx' of inr '1897.00' \
on your xxxx bank 'debit/credit/deposit/....' card ending '0000' is 0000'''
matches = re.finditer(regex, test_str)
for match in matches:
    print ("Match was found at {start}-{end}: {match}".format(start = match.start(), end = match.end(), match = match.group()))

---

？请使用代码缩进设置问题的格式

import re    
regex = r"'[^']*'"    
test_str = '''one time password for your transaction at, 'xxxx' of inr '1897.00' \
on your xxxx bank 'debit/credit/deposit/....' card ending '0000' is 0000'''
matches = re.finditer(regex, test_str)
for match in matches:
    print ("Match was found at {start}-{end}: {match}".format(start = match.start(), end = match.end(), match = match.group()))