在多个1D数组中查找长度最小的数组[PYTHON]

Python中是否有内置函数来实现这一点，或者我必须用传统的方法来实现。 例如

输出-A2

试试这个

A1 = [1,2,3]
A2 = [1]
A3 = [1.2]
print(min([A1,A2,A3],key=len))

输出：

[1]

试试这个

A1 = [1,2,3]
A2 = [1]
A3 = [1,2]
A = []
A = [A1, A2, A3] # make list of lists
min = 10000000 # some threshold 
for a in A: # iterate bigger list
    if(len(a) < min): # compare at each step
        min = len(a) # change value of min if condition is met
print(len(a)) # print reqd result

---

不是优雅的。一般来说，如果你想比较变量，你应该在某种类型的集合中包含变量：

d=[A1，A2，A3]

是一个列表列表，那么

min（d）

你想要列表的副本或引用吗？任何副本或引用都可以

A1 = [1,2,3]
A2 = [1]
A3 = [1,2]
A = []
A = [A1, A2, A3] # make list of lists
min = 10000000 # some threshold 
for a in A: # iterate bigger list
    if(len(a) < min): # compare at each step
        min = len(a) # change value of min if condition is met
print(len(a)) # print reqd result

1