python对象（）不接受任何参数错误

我不敢相信这实际上是个问题，但我一直在尝试调试这个错误，结果一无所获。我肯定我错过了一些非常简单的东西，因为这看起来太傻了

import Experiences, Places, Countries
class Experience(object):

    def make_place(self, place):
        addr = place["address"]
        addr = Places.ttypes.Address(addr["street"], addr["city"], addr["state"], Countries.ttypes._NAMES_TO_VALUES[addr["country"]], addr["zipcode"])
        ll = Geocoder.geocode(addr["street"]+", "+addr["city"]+", "+addr["state"]+" "+addr["zipcode"])
        place["location"] = Places.ttypes.Location(ll[0].coordinates[0], ll[0].coordinates[1])

    def __init__(self, exp_dict):
        exp_dict["datetimeInterval"] = Experiences.ttypes.DateTimeInterval(remove(exp_dict, "startTime"), remove(exp_dict, "endTime"))
        exp_dict["type"] = Experiences.ttypes.ExperienceType.OPEN
        exp_dict["place"] = self.make_place(exp_dict["place"])
        self.obj = Experiences.ttypes.Experience(**exp_dict)

@client.request
@client.catchClientException
def addExperience(thrift, access_token, exp_dict):
    experience = Experience(exp_dict)
    return thrift.client.addExperience(thrift.CLIENT_KEY, access_token, experience.obj)

（与addExperience相对应的两个修饰符是，因为这是在声明其类的文件之外定义的。）

我得到的错误是：

experience = Experience(exp_dict)
TypeError: object() takes no parameters

这对我来说没有任何意义，因为我清楚地向init函数声明了第二个参数。任何帮助都会很棒

Traceback (most recent call last):
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1836, in __call__
    return self.wsgi_app(environ, start_response)
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1820, in wsgi_app
    response = self.make_response(self.handle_exception(e))
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1403, in handle_exception
    reraise(exc_type, exc_value, tb)
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1817, in wsgi_app
    response = self.full_dispatch_request()
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1477, in full_dispatch_request
    rv = self.handle_user_exception(e)
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1381, in handle_user_exception
    reraise(exc_type, exc_value, tb)
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-packages/flask/app.py", line 1475, in full_dispatch_request
    rv = self.dispatch_request()
  File "/Users/phil/Hangify/hy-frontend-server/env/lib/python2.7/site-    packages/flask/app.py", line 1461, in dispatch_request
    return self.view_functions[rule.endpoint](**req.view_args)
  File "/Users/phil/Hangify/hy-frontend-server/hangify/session.py", line 22, in check_login
    return f()
  File "/Users/phil/Hangify/hy-frontend-server/hangify/handlers/create.py", line 31, in Handle
    res = exp.addExperience(hangify.thrift_interface, access_token, experience)
  File "/Users/phil/Hangify/hy-frontend-server/hangify/client/__init__.py", line 22, in decorator
    obj = func(client, *args, **kwargs)
  File "/Users/phil/Hangify/hy-frontend-server/hangify/client/__init__.py", line 30, in decorator
    return func(*args, **kwargs)
  File "/Users/phil/Hangify/hy-frontend-server/hangify/client/exp.py", line 39, in addExperience
    experience = Experience(exp_dict)
TypeError: object() takes no parameters

下面是Experience.mro（）-它表示类Experience的正确模块位置：

[<class 'hangify.client.exp.Experience'>, <type 'object'>]

 ['__class__', '__delattr__', '__dict__', '__doc__', '__format__',
 '__getattribute__', '__hash__', '__init__', '__module__', '__new__',
 '__reduce__', '__reduce_ex__', '__repr__', '__setattr__',
 '__sizeof__', '__str__', '__subclasshook__', '__weakref__', 'make_place']

---

您混合了制表符和空格

\uuuu init\uuuu

实际上是嵌套在另一个方法中定义的，因此您的类没有自己的

\uuuuu init\uuuu

方法，而是继承

对象。在记事本中打开代码，而不是在使用任何编辑器，您将看到Python的选项卡处理规则看到的代码

这就是为什么你不应该混合标签和空格。坚持这样或那样。建议使用空格。
您必须在每次点击时按两次和（_）键，它必须看起来像：

__init__

我为此挣扎了一会儿。
\uuuu init\uuuu
的愚蠢规则。两个“_uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu。顺便说一句，我输入了\uuuuu int\uuu而不是\uuuu init\uuu

我认为，在许多输入错误的情况下，我使用的IDE（IntelliJ）会将颜色更改为函数定义的默认设置。但是，在我的例子中，作为另一种dunder/magic方法，颜色与IDE为\uuuuuu init\uuuuuu显示的颜色相同（默认预定义项定义颜色），这花了我一段时间才发现缺少的我
什么是
经验
什么是
经验。t类型
？经验很重要，但我认为这与此无关。例如，当我从继承链中删除对象时，错误变成了
TypeError:这个构造函数不带参数
@phileaton:什么类的类方法？我怀疑
经验（exp_dict）
并不是指你认为的课程。您能否创建一个自包含的示例来演示该问题？您能否显示异常的完整回溯？除非
Experience
在包含
addExperience
的任何名称空间中被重新定义，否则该异常没有意义。问题包含正确的
\uuuuuu init\uuuuu
。之所以出现此错误，是因为在我的情况下我草率地只编写了
\uuuu init（）
-多么蹩脚的错误：D自视1h vs SO 3m来解决问题：Plol，我也犯了同样的错误，但找不到它。您的评论帮助我交叉检查了我使用的默认方法。谢谢：）