Python：创建显示两列之间相同行条目移位的输出

目标是查看两个列之间的差异，每个列包含相同的行条目，只是在不同的行上

[
["ENSCAFG00000008901","ENSCAFG00000013762"],
["ENSCAFG00000029470","ENSCAFG00000003029"],
["ENSCAFG00000013782","ENSCAFG00000007249"],
["ENSCAFG00000000806","ENSCAFG00000012468"],
["ENSCAFG00000013341","ENSCAFG00000018167"],
["ENSCAFG00000003376","ENSCAFG00000003376"],
["ENSCAFG00000000812","ENSCAFG00000018164"],
["ENSCAFG00000012468","ENSCAFG00000001591"],
["ENSCAFG00000031786","ENSCAFG00000013782"],
["ENSCAFG00000000803","ENSCAFG00000030793"],
["ENSCAFG00000003029","ENSCAFG00000015177"],
["ENSCAFG00000011565","ENSCAFG00000005750"]
]

这个列表有很多行，所以我不能手工完成。例如，我们在第一列的第11行和第二列的第2行看到ENSCAFG0000003029。我想创建一些输出，显示第一列和第二列之间相对于第一列的行移位。因此，在ENSCAFG0000003029的情况下，我希望在第一列中出现ENSCAFG0000003029的行之后看到+9或类似的内容

---

我希望我的目标是明确的，这是提出问题的正确地点

我想你得循环两次。例如，如果简化假设第一列中的条目是唯一的，则可以执行以下操作：

cols = [['ENSCAFG00000008901', 'ENSCAFG00000013762'],
        ['ENSCAFG00000029470', 'ENSCAFG00000003029'],
        ['ENSCAFG00000013782', 'ENSCAFG00000007249'],
        ['ENSCAFG00000000806', 'ENSCAFG00000012468'],
        ['ENSCAFG00000013341', 'ENSCAFG00000018167'],
        ['ENSCAFG00000003376', 'ENSCAFG00000003376'],
        ['ENSCAFG00000000812', 'ENSCAFG00000018164'],
        ['ENSCAFG00000012468', 'ENSCAFG00000001591'],
        ['ENSCAFG00000031786', 'ENSCAFG00000013782'],
        ['ENSCAFG00000000803', 'ENSCAFG00000030793'],
        ['ENSCAFG00000003029', 'ENSCAFG00000015177'],
        ['ENSCAFG00000011565', 'ENSCAFG00000005750']]
positions = dict((x[0], i) for i, x in enumerate(cols))
[positions[x[1]]-i for i, x in enumerate(cols) if x[1] in positions]

输出：

[9, 4, 0, -6]

---

对于很长的列表来说，它不会很有效，但这应该是可行的：

lst = [
    ["ENSCAFG00000008901","ENSCAFG00000013762"],
    ["ENSCAFG00000029470","ENSCAFG00000003029"],
    ["ENSCAFG00000013782","ENSCAFG00000007249"],
    ["ENSCAFG00000000806","ENSCAFG00000012468"],
    ["ENSCAFG00000013341","ENSCAFG00000018167"],
    ["ENSCAFG00000003376","ENSCAFG00000003376"],
    ["ENSCAFG00000000812","ENSCAFG00000018164"],
    ["ENSCAFG00000012468","ENSCAFG00000001591"],
    ["ENSCAFG00000031786","ENSCAFG00000013782"],
    ["ENSCAFG00000000803","ENSCAFG00000030793"],
    ["ENSCAFG00000003029","ENSCAFG00000015177"],
    ["ENSCAFG00000011565","ENSCAFG00000005750"]
    ]

col_1 = [x[0] for x in lst]
col_2 = [x[1] for x in lst]

idx_offset = [None] * len(col_1)
for col_1_idx, val_1 in enumerate(col_1):
    try:
        col_2_idx = col_2.index(val_1)
    except ValueError:
        continue
    idx_offset[col_1_idx] = col_2_idx - col_1_idx

简而言之，对于第一列中的每个值，在第二列中找到该值的索引（如果存在）。取这个索引，从中减去第一列中值的索引，这就是您的输出。对于第一列中未出现在第二列中的元素，输出idx_偏移量将为无。在这种情况下，输出将变为：

[None, None, 6, None, None, 0, None, -4, None, None, -9, None]

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这是我想要的输出，然而，当我输入这个时，我没有得到输出或者你在文章中描述的任何输出。此外，是否有一种简单的方法可以将输出附加到它们所属的行？上述方法确实不会产生输出。您可以轻松地创建原始列表的新副本，并附加索引偏移量：outp=[[val_1，val_2，idx]用于val_1，val_2，zipcol_1中的idx，col_2，idx_offset]

[None, None, 6, None, None, 0, None, -4, None, None, -9, None]