Python 从异常对象获取行号

我已经定义了一个自定义异常对象，并希望获得异常的行号

class FlowException(Exception):
    pass

def something():
    print 2/3
    print 1/2
    print 2/0


try:
   something()
except Exception as e:
   raise FlowException("Process Exception", e)

现在，如果something（）中存在异常，它会抛出FlowException，但没有给出确切的行号，那么如何从FlowException中获取行号（即，当它执行2/0时失败）

以下是输出：--

在Python3.6上测试

class FlowException(Exception):
    pass

def something():
    raise ValueError

try:
   something()
except Exception as e:
    raise FlowException("Process Exception", e)

输出具有行号：

Traceback (most recent call last):
  File "/Users/diman/PycharmProjects/invites/test.py", line 8, in <module>
    something()
  File "/Users/diman/PycharmProjects/invites/test.py", line 5, in something
    raise ValueError
ValueError

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "/Users/diman/PycharmProjects/invites/test.py", line 10, in <module>
    raise FlowException("Process Exception", e)
__main__.FlowException: ('Process Exception', ValueError())

对象在

tb\u lineno

属性中保存该信息：

import sys

# ...
except Exception as e:
   trace_back = sys.exc_info()[2]
   line = trace_back.tb_lineno
   raise FlowException("Process Exception in line {}".format(line), e)

您可以使用模块

---

查看如何使用它。

在Python3上打印

FlowException

时，您会得到一个错误，如“在处理[original exception stack]时遇到FlowException[flow exception stack]”可能是

import logging
logger = logging.getLogger()

try:
    something()
except Exception as e:
    logger.exception(e)
    raise FlowException("Process Exception", e)

import sys

# ...
except Exception as e:
   trace_back = sys.exc_info()[2]
   line = trace_back.tb_lineno
   raise FlowException("Process Exception in line {}".format(line), e)