Python中两个列表中字符串中的常用字符

我有两份清单如下：

a = ["Ron is great", "Mark is good", "Sheela is bad", "Amy is horrible"]
b = ["Ron", "Mark"]
c = [item for item in a if item in b]

我通常使用上面的列表理解来查找两个列表之间的公共元素。但是，在上面的场景中，它失败了，因为in函数进行了精确匹配，因此c是一个空列表。我如何绕过这一点，并尝试获得一个如下所示的列表c：

c=["Ron is great", "Mark is good"]

---

使用列表表达式解决了您的问题

>>> a = ["Ron is great", "Mark is good", "Sheela is bad", "Amy is horrible"]
>>> b = ["Ron", "Mark"]
>>> c= [
...     sentence
...     for word in b
...     for sentence in a
...     if word in sentence
... ]                

['Ron is great', 'Mark is good']

---

使用列表表达式解决了您的问题

>>> a = ["Ron is great", "Mark is good", "Sheela is bad", "Amy is horrible"]
>>> b = ["Ron", "Mark"]
>>> c= [
...     sentence
...     for word in b
...     for sentence in a
...     if word in sentence
... ]                

['Ron is great', 'Mark is good']

---

例如，您将需要两个循环

c = [item for item in a
     if any(name in item for name in b)]

---

应该足够了。例如，您需要两个循环

c = [item for item in a
     if any(name in item for name in b)]

应该足够了。

你可以这样试试

>>> a = ["Ron is great", "Mark is good", "Sheela is bad", "Amy is horrible"]
>>> b = ["Ron", "Mark"]
>>> [ item for item in a for word in b if word in item]
['Ron is great', 'Mark is good']
>>> 

你可以这样试试

>>> a = ["Ron is great", "Mark is good", "Sheela is bad", "Amy is horrible"]
>>> b = ["Ron", "Mark"]
>>> [ item for item in a for word in b if word in item]
['Ron is great', 'Mark is good']
>>>