Python 当我没有’；我没有具体说明

CreatePostView in views.py如何链接到post_form.html

它还没有“模板名称”，createpostview如何链接到post\u form.html

请查看我在下面添加的以下代码，如果您能提供帮助，请告诉我，谢谢

Views.py

from django.shortcuts import render, get_object_or_404, redirect
from django.contrib.auth.decorators import login_required
from django.utils import timezone
from .models import Post, Comment
from .forms import PostForm, CommentForm

from django.views.generic import (TemplateView,ListView,
                                  DetailView,CreateView,
                                  UpdateView,DeleteView)

from django.urls import reverse_lazy
from django.contrib.auth.mixins import LoginRequiredMixin

class CreatePostView(LoginRequiredMixin,CreateView):
    login_url = '/login/'
    redirect_field_name = 'blog/post_detail.html'

    form_class = PostForm

    model = Post

url.py

from django.urls import path
from . import views


urlpatterns = [
    path('post/new/', views.CreatePostView.as_view(), name='post_new'),
]

post_form.html

{% extends 'blog/base.html' %}

{% block content %}
    <h1>New post</h1>

    <form method="POST" class="post-form">
    {% csrf_token %}
    {{form.as_p}}
    <button type="submit" class="save btn btn-default">Save</button>
    </form>

    <script>var editor = new MediumEditor('.editable');</script>

{% endblock %}

{%extends'blog/base.html%}
{%block content%}
新职位
{%csrf_令牌%}
{{form.as_p}}
拯救
var editor=new MediumEditor（'.editable'）；
{%endblock%}

---

请帮助我理解这一点。

对于应用程序

myapp

中的模型

Post

，

CreateView

将使用模板

myapp/Post\u form.html

这只是

CreateView

的第一步

您可能会发现，在ccbv网站上查看该方法有助于了解代码的工作原理