Python 特殊方法“cmp”不起作用

这个特殊的工作不起作用。说出以下代码：

class Test():
      def __cmp__(self, other):
           return False

t1 = Test()
t2 = t1

print t2 == t1

我应该得到False，因为cmp总是返回False。但实际上，python对我来说是正确的

任何建议？

\uuuuu cmp\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu。返回False实际上会使其与所有内容进行比较，因为False的整数值为0

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还要注意的是_cmp__在Python3中被弃用并被忽略。您应该实现uuu eq_uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu。如果你运行它，你会得到_ucmp__;正好1个参数2。谢谢，丹尼尔，我已经修改了我的问题。我只是错过了第二个参数。不知道为什么投票会结束，这不是一个好问题，但也不是离题。嗨，Lennart，我正在使用2.6.2，只是使用cmp来学习Python的特殊方法。同样，您是对的，这个方法应该有两个参数。我更新了我的问题。嗨，勒纳特，你说得对。如果让cmp始终返回1或-1，我将通过t1==t2得到False，反之，如果让cmp返回0或False，将通过t1==t2得到True。@Geoffrey:不仅仅是t1==t2。t1==“whatever”也将返回True-是的，你是对的。我再次感到奇怪的是，为什么我会通过0==t1实现。我想我应该通过0==t1得到False。因为0应该从对象继承，对象应该在这里调用。\uuuuCMp\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu。在这种情况下，将以相反的顺序再次尝试比较。

class Test():
      def __cmp__(self, other):
           return -1