Python Dynamo DB扫描查询以获取JSON格式的输出文件

我对使用boto3的Dynamo DB还很陌生。我想：获取Dynamo DB中所有行的扫描，并将其以

JSON

格式存储在一个文件中，以便进行额外的数据处理

我目前正在使用下面显示的脚本获取详细信息（将涉及分页）：

这为我提供了5000行的示例输出：

{"info": {"rating": 6.5}, "year": 2004, "title": "The Polar Express"}
{"info": {"rating": 5.7}, "year": 2004, "title": "The Prince & Me"}
{"info": {"rating": 5.3}, "year": 2004, "title": "The Princess Diaries 2: Royal Engagement"}
{"info": {"rating": 6.3}, "year": 2004, "title": "The Punisher"}
{"info": {"rating": 6.8}, "year": 2004, "title": "The SpongeBob SquarePants Movie"}

我无法获得所需格式的输出（如下所示）。我在这里等文件

[
    {"info": {"rating": 6.5}, "year": 2004, "title": "The Polar Express"},
    {"info": {"rating": 5.7}, "year": 2004, "title": "The Prince & Me"},
    {"info": {"rating": 5.3}, "year": 2004, "title": "The Princess Diaries 2: Royal Engagement"},
    {"info": {"rating": 6.3}, "year": 2004, "title": "The Punisher"},
    {"info": {"rating": 6.8}, "year": 2004, "title": "The SpongeBob SquarePants Movie"}
]

---

有谁能给我一些关于如何进一步调查的提示或指点吗？

回复['Items']不是你要找的列表吗？Response是一个包含列表的词汇表，它只能是一个子集，所以如果需要，您需要迭代多个响应

参考：

[
    {"info": {"rating": 6.5}, "year": 2004, "title": "The Polar Express"},
    {"info": {"rating": 5.7}, "year": 2004, "title": "The Prince & Me"},
    {"info": {"rating": 5.3}, "year": 2004, "title": "The Princess Diaries 2: Royal Engagement"},
    {"info": {"rating": 6.3}, "year": 2004, "title": "The Punisher"},
    {"info": {"rating": 6.8}, "year": 2004, "title": "The SpongeBob SquarePants Movie"}
]