Python 验证列表中字符串的第一个字母是否为元音时出错，解决方案？

抱歉格式不好，这是我的第一篇文章。 我目前正试图从给定列表中返回以元音开头的单词列表，但它什么也不返回。有可能得到帮助吗

x = ["A","B","C","D","E","F",]
wordList = []
for i in x:
  if i[0].lower() == ['a','e','i','o','u']:
    wordList.append(i)
return wordList

试试这个，你会得到元音字母。对于以元音开头的单词，可以执行以下操作

 x = ["A","B","C","D","E","F",]
 wordList = []
 for i in x:
     if i[0].lower() in ['a','e','i','o','u']:
         wordList.append(i)
 return wordList

喜欢的话就投票。

另一种投票方式：

x = ["A","B","C","D","E","F",]
wordList = [ i for i in x if i.lower().startswith(('a','e','i','o','u')) ]

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单个字符不能等于整个列表。您应该在@usr2564301中使用

，非常感谢。这是否回答了您的问题？
x = ["A","B","C","D","E","F",]
wordList = [ i for i in x if i.lower().startswith(('a','e','i','o','u')) ]