Python 21点循环故障
所以我正在做一个21点模拟器来找出某些手牌赢或不赢的概率。我有一个while循环来循环一整副52张牌,直到剩下4张牌。在这里面,我有一个循环,让庄家抽签,直到他的计数达到17+,就像真正的21点。当我运行代码时,它将成功地运行一组代码,但每次只打印同一只手。代码如下:Python 21点循环故障,python,random,while-loop,blackjack,Python,Random,While Loop,Blackjack,所以我正在做一个21点模拟器来找出某些手牌赢或不赢的概率。我有一个while循环来循环一整副52张牌,直到剩下4张牌。在这里面,我有一个循环,让庄家抽签,直到他的计数达到17+,就像真正的21点。当我运行代码时,它将成功地运行一组代码,但每次只打印同一只手。代码如下: # <--- PROGRAM SETUP ---> import random # Drawing Card Function def draw_card(): # Card Values in 1 Deck
# <--- PROGRAM SETUP --->
import random
# Drawing Card Function
def draw_card():
# Card Values in 1 Deck
vals = [2,2,2,2,3,3,3,3,4,4,4,4,5,5,5,5,6,6,6,6,7,7,7,7,
8,8,8,8,9,9,9,9,10,10,10,10,10,10,10,10,10,10,10,
10,10,10,10,10,10,10,10,10,11,11,11,11]
# </--->
dealer = 0
player = 0
bust = 21
deck_count = 0
hand_count = 0
dealer_cards = []
# <--- // --->
cards = 52
# Loop Hands Through Deck
while(cards > 4):
# Draw Card Loop
while(dealer <= 16):
card = random.choice(vals)
vals.remove(card)
dealer_cards.append(card)
dealer = dealer + card
hand_count = hand_count + 1
cards = cards - len(dealer_cards)
# <--- Results --->
if 17 <= dealer <= 21:
print "Hand: {}, Dealer Stands @ {}".format(hand_count, dealer)
for i in dealer_cards:
print "Card: {}".format(i)
else:
print "Hand: {}, Dealer Busts @ {}".format(hand_count, dealer)
for i in dealer_cards:
print "Card: {}".format(i)
else:
deck_count = deck_count + 1
print "Deck {} is finished!".format(deck_count)
# <--- // --->
draw_card()
我可以修正什么使每只手都是唯一的画,而不是多次打印第一手?谢谢在循环迭代之间,您实际上并没有清理经销商的手 因此,他可以只抽一张卡,从他19岁起,永远坚持下去,跳过内部
,而庄家<17
循环,从你的虚拟资金中攫取你的所有资金,因为他知道他有一手相当不错的牌
只需在结果if/else检查后设置
dealer=0
。在循环迭代之间,您实际上并没有清除dealer的手
因此,他可以只抽一张卡,从他19岁起,永远坚持下去,跳过内部,而庄家<17
循环,从你的虚拟资金中攫取你的所有资金,因为他知道他有一手相当不错的牌
只需在结果if/else检查后设置
dealer=0
。您忘记在每次迭代之前重置dealer
和dealer\u卡
,因此您的while(dealer 4):
经销商卡=[]
经销商=0
#抽卡环
while(经销商您忘记在每次迭代之前重置经销商和经销商卡,因此您的while(经销商4):
经销商卡=[]
经销商=0
#抽卡环
虽然(庄家当<代码>庄家>16
和<代码>牌>4
时,循环会无休止地继续。重新思考你的不变量。当<代码>庄家>16
和<代码>牌>4
时,循环会无休止地继续。重新思考你的不变量。修复后,现在你需要正确处理ACE。很少有赌场站在软17上,当然也没有赌场t两个a作为半身像,就像这个代码一样。在这个问题解决之后,现在你需要正确处理a。很少有赌场站在soft 17上,当然没有一家像这个代码那样将两个a作为半身像来计算。
Hand: 1, Dealer Stands @ 19
Card: 10
Card: 9
Hand: 2, Dealer Stands @ 19
Card: 10
Card: 9
Hand: 3, Dealer Stands @ 19
Card: 10
Card: 9
Hand: 4, Dealer Stands @ 19
Card: 10
Card: 9
Hand: 5, Dealer Stands @ 19
Card: 10
Card: 9
Hand: 6, Dealer Stands @ 19
Card: 10
Card: 9
Hand: 7, Dealer Stands @ 19
Card: 10
Card: 9
Hand: 8, Dealer Stands @ 19
Card: 10
Card: 9
Hand: 9, Dealer Stands @ 19
Card: 10
Card: 9
Hand: 10, Dealer Stands @ 19
...All the way till the deck has less than 4 cards left.
while(cards > 4):
dealer_cards = []
dealer = 0
# Draw Card Loop
while(dealer <= 16):
card = random.choice(vals)
vals.remove(card)
dealer_cards.append(card)
dealer = dealer + card
...