Python while循环或条件

在第二个while循环中，我被卡住了，永远也出不去。如何修复

def playGame(wordList):

new_hand = {}

choice = input('Enter n to deal a new hand, or e to end game: ')   
while choice != 'e':
    if choice == 'n':
        player_or_pc = input('Enter u to have yourself play, c to have the computer play: ')
        while player_or_pc != 'u' or player_or_pc != 'c':
            print('Invalid command.')
            player_or_pc = input('Enter u to have yourself play, c to have the computer play: ')                  
        if player_or_pc == 'u':
            print('player played the game')
        elif player_or_pc == 'c':
            print('PC played the game')
        choice = input('Enter n to deal a new hand, r to replay the last hand, or e to end game: ')
    else:
        print('Invalid command.')
        choice = input('Enter n to deal a new hand, r to replay the last hand, or e to end game: ')

---

播放器或pc！='u'或播放器或pc！='c'

始终为真：

• 如果

  player\u或

  为

  'u'

  ，则不等于

  'c'

  ，因此这两个条件之一为真
• 如果

  player\u或

  为

  'c'

  ，则不等于

  'u'

  ，因此这两个条件之一为真
• 两个条件都为真的任何其他值

使用

和
：

while player_or_pc != 'u' and player_or_pc != 'c':

或者使用
=
，将整个内容放在括号中，并在前面使用
而不是
：

while not (player_or_pc == 'u' or player_or_pc == 'c'):

在这一点上，使用成员资格测试更为清晰：

while player_or_pc not in {'u', 'c'}:

替换

while player_or_pc != 'u' or player_or_pc != 'c':

与

否则，
player\u或\u pc
应该等于
u
和
c
，这是不可能的。
player\u或\u pc！='u'或播放器或pc！='c'
-此条件始终为真。听起来你想要的是
和
，而不是
或
。
while player_or_pc != 'u' and player_or_pc != 'c':