Python 创建坐标列表_Python_Coordinates

Python 创建坐标列表

python

Python 创建坐标列表,python,coordinates,Python,Coordinates,假设我的最大图像大小是 totalpixels = (45, 45) 我想将此图像拆分为 split_image = (10,20) #split the 45x45 pixels into 10x20 pixels 当我将45x45图像分割成10x20时，我可以得到的坐标列表是 [(0,0), (10,0), (20,0), (30,0), (0,20), (10,20), (20,20), (30,20)] 因此，我从（0,0）坐标开始，然后从这里添加 (0,0) (10,0)

假设我的最大图像大小是

totalpixels = (45, 45)

我想将此图像拆分为

split_image = (10,20) #split the 45x45 pixels into 10x20 pixels

当我将45x45图像分割成10x20时，我可以得到的坐标列表是

[(0,0), (10,0), (20,0), (30,0), (0,20), (10,20), (20,20), (30,20)]

因此，我从（0,0）坐标开始，然后从这里添加

(0,0)
(10,0)    = (10,0)
(10+10,0) = (20,0)
(20+10,0) = (30,0)
(0,0+20)  = (0,20)    
(0+10,20) = (10,20)
(10+10,20)= (20,20)
(20+10,20)= (30,20)

我假设我要做两个for循环

for x in range(total[0]): #Is the range supposed to be this?
    for y in range(total[1]):
         #I'm not sure how to append values according to the split value

我认为您希望使用带有步骤参数的范围：

range(start, stop[, step])

所以你可以这样做：

>>> result = []
>>> totalpixels = (45, 45) 
>>> split_image = (10,20) #split the 45x45 pixels into 10x20 pixels
>>> for x in range(0, totalpixels[0], split_image[0]):
...     for y in range(0, totalpixels[1], split_image[1]):
...             result.append((x,y))
... 
>>> result
[(0, 0), (0, 20), (0, 40), (10, 0), (10, 20), (10, 40), (20, 0), (20, 20), (20, 40), (30, 0), (30, 20), (30, 40), (40, 0), (40, 20), (40, 40)]
>>>

>>> [(x, y) for x in range(0, totalpixels[0], split_image[0]) for y in range(0, totalpixels[1], split_image[1])]
[(0, 0), (0, 20), (0, 40), (10, 0), (10, 20), (10, 40), (20, 0), (20, 20), (20, 40), (30, 0), (30, 20), (30, 40), (40, 0), (40, 20), (40, 40)]

这将生成分割图像的坐标，如下所示：

>>> result = []
>>> totalpixels = (45, 45) 
>>> split_image = (10,20) #split the 45x45 pixels into 10x20 pixels
>>> for x in range(0, totalpixels[0], split_image[0]):
...     for y in range(0, totalpixels[1], split_image[1]):
...             result.append((x,y))
... 
>>> result
[(0, 0), (0, 20), (0, 40), (10, 0), (10, 20), (10, 40), (20, 0), (20, 20), (20, 40), (30, 0), (30, 20), (30, 40), (40, 0), (40, 20), (40, 40)]
>>>

0 10 20 30 40 45 +-----+-----+-----+-----+--+ | | | | | | | | | | | | 20 +-----+-----+-----+-----+--+ | | | | | | | | | | | | 40 +-----+-----+-----+-----+--+ | | | | | | 45 +-----+-----+-----+-----+--+ 0 10 20 30 40 45 +-----+-----+-----+-----+--+ | | | | | | | | | | | | 20 +-----+-----+-----+-----+--+ | | | | | | | | | | | | 40 +-----+-----+-----+-----+--+ | | | | | | 45 +-----+-----+-----+-----+--+

希望我能提供帮助。

我认为您希望使用带步骤的范围参数：

range(start, stop[, step])

所以你可以这样做：

>>> result = []
>>> totalpixels = (45, 45) 
>>> split_image = (10,20) #split the 45x45 pixels into 10x20 pixels
>>> for x in range(0, totalpixels[0], split_image[0]):
...     for y in range(0, totalpixels[1], split_image[1]):
...             result.append((x,y))
... 
>>> result
[(0, 0), (0, 20), (0, 40), (10, 0), (10, 20), (10, 40), (20, 0), (20, 20), (20, 40), (30, 0), (30, 20), (30, 40), (40, 0), (40, 20), (40, 40)]
>>>

>>> [(x, y) for x in range(0, totalpixels[0], split_image[0]) for y in range(0, totalpixels[1], split_image[1])]
[(0, 0), (0, 20), (0, 40), (10, 0), (10, 20), (10, 40), (20, 0), (20, 20), (20, 40), (30, 0), (30, 20), (30, 40), (40, 0), (40, 20), (40, 40)]

这将生成分割图像的坐标，如下所示：

>>> result = []
>>> totalpixels = (45, 45) 
>>> split_image = (10,20) #split the 45x45 pixels into 10x20 pixels
>>> for x in range(0, totalpixels[0], split_image[0]):
...     for y in range(0, totalpixels[1], split_image[1]):
...             result.append((x,y))
... 
>>> result
[(0, 0), (0, 20), (0, 40), (10, 0), (10, 20), (10, 40), (20, 0), (20, 20), (20, 40), (30, 0), (30, 20), (30, 40), (40, 0), (40, 20), (40, 40)]
>>>

希望我能帮忙。

for

不需要循环：

>>> [(x, y) for x in range(0, 31, 10) for y in range(0, 21, 20)]
[(0, 0), (0, 20), (10, 0), (10, 20), (20, 0), (20, 20), (30, 0), (30, 20)]

此列表将生成您指定的结果

range的参数是start、stop和step。您为x指定的步长值为10，为y指定的步长值为20。请注意，

range

在“stop”值（其第二个参数）之前停止。因此，如果希望最高的“x”值为30，则需要使“stop”刚好大于该值

您似乎需要大小为split_image的所有像素块的边缘坐标，从（0，0）开始，这些像素块适合大小为totalpixels的图像，但不会超出该图像。计算该值的一般函数为：

def coords(split_image, totalpixels):
    xstop = totalpixels[0] - split_image[0]
    ystop = totalpixels[1] - split_image[1]
    return [(x, y) for x in range(0, xstop, split_image[0])
            for y in range(0, ystop, split_image[1])]

在参数值上运行时，它会生成：

>>> coords( (10, 20), (45, 45) )
[(0, 0), (0, 20), (10, 0), (10, 20), (20, 0), (20, 20), (30, 0), (30, 20)]

for

不需要循环：

>>> [(x, y) for x in range(0, 31, 10) for y in range(0, 21, 20)]
[(0, 0), (0, 20), (10, 0), (10, 20), (20, 0), (20, 20), (30, 0), (30, 20)]

此列表将生成您指定的结果

range的参数是start、stop和step。您为x指定的步长值为10，为y指定的步长值为20。请注意，

range

在“stop”值（其第二个参数）之前停止。因此，如果希望最高的“x”值为30，则需要使“stop”刚好大于该值

def coords(split_image, totalpixels):
    xstop = totalpixels[0] - split_image[0]
    ystop = totalpixels[1] - split_image[1]
    return [(x, y) for x in range(0, xstop, split_image[0])
            for y in range(0, ystop, split_image[1])]

在参数值上运行时，它会生成：

>>> coords( (10, 20), (45, 45) )
[(0, 0), (0, 20), (10, 0), (10, 20), (20, 0), (20, 20), (30, 0), (30, 20)]

“分割值”是什么意思？我不明白这个问题。你能正确地解释这个问题吗？你说的分割值是什么意思？我不明白这个问题。你能正确地解释这个问题吗？John1024的解决方案对于循环来说更像是pythonic而不是显式的。另一种方法是

zip（范围（0,31,10），范围（0,21,20））

，它还返回坐标列表。如果不想同时在内存中存储大量磁贴坐标，请使用xrange和itertools.izip。John1024的解决方案比显式for循环更具pythonic。另一种方法是

zip（范围（0,31,10），范围（0,21,20））

，它还返回坐标列表。如果不希望同时在内存中存储大量磁贴坐标，请使用xrange和itertools.izip。