Python 如何按块获取线

下面的问题很简单

根据下面的代码，“数据”由一列数字组成，比如说12个数字（见下文）

如何创建由四个数字组成的块？比如说

56.71739
56.67950
56.65762
56.63320

56.61648
56.60323
56.63215
56.74365

等等。。。因为我需要处理所有的块

---

感谢阅读

，

itertools

模块提供了一个配方，可满足您的需要：

from itertools import izip_longest

def grouper(n, iterable, fillvalue=None):
    "grouper(3, 'ABCDEFG', 'x') --> ABC DEF Gxx"
    args = [iter(iterable)] * n
    return izip_longest(fillvalue=fillvalue, *args)

这看起来像：

>>> corpus = (56.71739, 56.67950, 56.65762, 56.63320, 56.61648,
...           56.60323, 56.63215, 56.74365, 56.98378, 57.34681,
...           57.78903, 58.27959,)
>>> list(grouper(4, corpus))
[(56.71739, 56.6795, 56.65762, 56.6332),
 (56.61648, 56.60323, 56.63215, 56.74365),
 (56.98378, 57.34681, 57.78903, 58.27959)]
>>> print '\n\n'.join('\n'.join(group)
...                   for group
...                   in grouper(4, map(str, corpus)))
56.71739
56.6795
56.65762
56.6332

56.61648
56.60323
56.63215
56.74365

56.98378
57.34681
57.78903
58.27959
>>> 

---

非常感谢！我的数据实际上比我在这里发布的要复杂得多，但你给了我一个非常好的输入。我将尝试修改它并将其粘贴到我的代码中！干杯，伙计们

>>> corpus = (56.71739, 56.67950, 56.65762, 56.63320, 56.61648,
...           56.60323, 56.63215, 56.74365, 56.98378, 57.34681,
...           57.78903, 58.27959,)
>>> list(grouper(4, corpus))
[(56.71739, 56.6795, 56.65762, 56.6332),
 (56.61648, 56.60323, 56.63215, 56.74365),
 (56.98378, 57.34681, 57.78903, 58.27959)]
>>> print '\n\n'.join('\n'.join(group)
...                   for group
...                   in grouper(4, map(str, corpus)))
56.71739
56.6795
56.65762
56.6332

56.61648
56.60323
56.63215
56.74365

56.98378
57.34681
57.78903
58.27959
>>>