Python 如何拦截实例方法调用?

Python 如何拦截实例方法调用?,python,function,call,instance,getattr,Python,Function,Call,Instance,Getattr,我在下面的类MyWrapper中寻找拦截实例方法调用的方法: class SomeClass1: def a1(self): self.internal_z() return "a1" def a2(self): return "a2" def internal_z(self): return "z" class SomeClass2(SomeClass1): pass class MyWrapp

我在下面的类
MyWrapper
中寻找拦截实例方法调用的方法:

class SomeClass1:
    def a1(self):
        self.internal_z()
        return "a1"
    def a2(self):
        return "a2"
    def internal_z(self):
        return "z"

class SomeClass2(SomeClass1):
    pass

class MyWrapper(SomeClass2):

    # def INTERCEPT_ALL_FUNCTION_CALLS():
    #      result = Call_Original_Function()
    #      self.str += result  
    #      return result  


    def __init__(self):
        self.str = ''
    def getFinalResult(self):
        return self.str

x = MyWrapper()
x.a1()
x.a2()
我想截获通过包装器类进行的所有函数调用。在我的包装器类中,我希望跟踪所有结果字符串

result = x.getFinalResult()
print result == 'a1a2'

一些快速而肮脏的代码:

class Wrapper:
    def __init__(self, obj):
        self.obj = obj
        self.callable_results = []

    def __getattr__(self, attr):
        print("Getting {0}.{1}".format(type(self.obj).__name__, attr))
        ret = getattr(self.obj, attr)
        if hasattr(ret, "__call__"):
            return self.FunctionWrapper(self, ret)
        return ret

    class FunctionWrapper:
        def __init__(self, parent, callable):
            self.parent = parent
            self.callable = callable

        def __call__(self, *args, **kwargs):
            print("Calling {0}.{1}".format(
                  type(self.parent.obj).__name__, self.callable.__name__))
            ret = self.callable(*args, **kwargs)
            self.parent.callable_results.append(ret)
            return ret

class A:
    def __init__(self, val): self.val = val
    def getval(self): return self.val

w = Wrapper(A(10))
print(w.val)
w.getval()
print(w.callable_results)

可能不彻底,但我想这可能是一个不错的起点。

您可以在实例化时使用装饰程序包装您的方法:

#!/usr/bin/env python

import inspect

def log(func):
    def _logged(*args, **kw):
        print "[LD] func", func.__name__, "called with:", args, kw
        result = func(*args, **kw)
        print "[LD] func", func.__name__, "returned:", result
        return result
    return _logged

class A(object):
    def __init__(self):
        for x in inspect.getmembers(self, (inspect.ismethod)):
            if not x[0].startswith('__'):
                setattr(self, x[0], log(getattr(self, x[0])))

    def hello(self):
        print "Hello"

    def bye(self):
        print "Bye"
        return 0
现在,如果您呼叫
hello
bye
,呼叫首先通过
log

a = A()
a.hello()
a.bye()

# [LD] func hello called with: () {}
# Hello
# [LD] func hello returned: None
# [LD] func bye called with: () {}
# Bye
# [LD] func bye returned: 0

你想做的事和我的很相似。 您应该以相反的顺序使用示例代码,我的意思是创建一个类来记录方法调用的返回值,并使您想要查看的类从中继承。 这样的话

class RetValWatcher(object):
    def __init__(self):
        self.retvals = []

    def __getattribute__(self, name):
        attr = super(RetValWatcher, self).__getattribute__(name)
        if callable(attr):
            def wrapped(*args, **kwargs):
                retval = attr(*args, **kwargs)
                self.retvals.append(retval)
                return retval
            return wrapped
        else:
            return attr

    def getFinalRestult(self):
        return ''.join(self.retvals)

class MyClass(RetValWatcher):
    def a(self):
        self.internal_z()
        return 'a1'

    def b(self):
        return 'b1'

    def internal_z(self):
        return 'z'

x = MyClass()
x.a()
x.b()
print x.getFinalResult()
#'za1b1'
通过一些微小的更改,此方法还允许您记录所有RetValWatcher实例的返回值

编辑:添加了奇点评论建议的更改


Edit2:忘记处理attr不是方法的情况(再次出现thx奇点)

很高兴知道-不客气。请将答案标记为“已接受”:+1,我更喜欢这种方法,但我有一些意见:1)用
self.retvals=[]
替换
retvals=[]
,2)在OP
x的情况下,getFinalResult()
将返回za1a2而不是a1a2,3)我认为最好使用
inspect.ismethod
callable(attr)
而不是
hasattr(attr,'.\u call'.\uu')
。缺少的“self”只是一个疏忽,但其他两点你是对的。编辑;)啊,再次抱歉;您忘记了
else:if callable(attr):
返回attr
,因为您不想模糊属性调用:)输入错误:
def getfinalresttult(self):