Python 匹配txt文件中的每个单词

我正在研究一个项目Euler问题（为了好玩）。 它附带一个46kbtxt文件，其中包含一行5000多个名称的列表，格式如下：

"MARIA","SUSAN","ANGELA","JACK"...

我的计划是编写一个方法来提取每个名称并将它们附加到Python列表中。正则表达式是解决这个问题的最好武器吗？

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我查阅了Pythonredoc，但是我很难找到正确的正则表达式

这看起来像是一种格式，模块将对此有所帮助。如果文件的格式与您所说的一样，即

这是单行线

格式如下：“玛丽亚”、“苏珊”、“安吉拉”、“杰克”

那么这应该是可行的：

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regexp可以完成这项工作，但效率很低。使用csv是可行的，但它可能无法很好地处理一行中的5000个单元格。至少它必须在内存中加载整个文件并维护整个名称列表（这对您来说可能不是问题，因为这是一个非常小的数据量）。如果您想要一个用于相对较大文件（远远大于5000个名称）的迭代器，状态机将完成以下任务：

def parse_chunks(iter, quote='"', delim=',', escape='\\'):
    in_quote = False
    in_escaped = False

    buffer = ''

    for chunk in iter:
        for byte in chunk:
            if in_escaped:
                # Done with the escape char, add it to the buffer
                buffer += byte
                in_escaped = False            
            elif byte == escape:
                # The next charachter will be added literally and not parsed
                in_escaped = True          
            elif in_quote:
                if byte == quote:
                    in_quote = False
                else:
                    buffer += byte
            elif byte == quote:
                in_quote = True
            elif byte in (' ', '\n', '\t', '\r'):
                # Ignore whitespace outside of quotes
                pass
            elif byte == delim:
                # Done with this block of text
                yield buffer
                buffer = ''                    
            else:
                buffer += byte

    if in_quote:
        raise ValueError('Found unbalanced quote char %r' % quote)
    elif in_escaped:
        raise ValueError('Found unbalanced escape char %r' % escape)

    # Yield the last bit in the buffer
    yield buffer

data = r"""
"MARIA","SUSAN",
"ANG
ELA","JACK",,TED,"JOE\""
"""
print list(parse_chunks(data))

# ['MARIA', 'SUSAN', 'ANG\nELA', 'JACK', '', 'TED', 'JOE"']

# Use a fixed buffer size if you know the file has only one long line or
# don't care about line parsing
buffer_size = 4096
with open('myfile.txt', 'r', buffer_size) as file:
    for name in parse_chunks(file):
        print name

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如果你能做得更简单，那就做得更简单。无需使用csv模块。我认为5000个名字或46KB不足以让人担心

names = []
f = open("names.txt", "r")

# In case there is more than one line...
for line in f.readlines():
    names = [x.strip().replace('"', '') for x in line.split(",")]

print names
#should print ['name1', ... , ...]

names = []
f = open("names.txt", "r")

# In case there is more than one line...
for line in f.readlines():
    names = [x.strip().replace('"', '') for x in line.split(",")]

print names
#should print ['name1', ... , ...]