python如何将转义的非unicode字符替换为它们各自的'；雷亚尔'；utf-8

我对编程比较陌生，在为spotify for ubuntu（linux）编写一个与Snip相当的python时遇到了一个小问题 不知何故，我可以正确地编码标题，但我无法以同样的方式编码艺术家

当我尝试以同样的方式对艺术家进行编码时，我得到了以下结果：

File "./songfinder.py", line 11, in currentplaying
    artiststr = str((metadata['xesam:artist']).encode('utf-8'))
AttributeError: 'dbus.Array' object has no attribute 'encode'

然而，标题是完全一样的，这是工作

到目前为止，代码仍在运行，但有\xd8而不是Ø，以及类似的代码：

import dbus
session_bus = dbus.SessionBus()
spotify_bus = session_bus.get_object("org.mpris.MediaPlayer2.spotify", "/org/mpris/MediaPlayer2")
spotify_properties = dbus.Interface(spotify_bus, "org.freedesktop.DBus.Properties")

def currentplaying():
    metadata = spotify_properties.Get("org.mpris.MediaPlayer2.Player", "Metadata")
    title =  str((metadata['xesam:title']).encode('utf-8'))
    artiststr = str((metadata['xesam:artist']))
    if ("dbus.string" in artiststr.lower()):
        artists = artiststr.split("(u")
        artist = artists[1]
        artists = artist.split(")],")
        artist = artists[0]
        artist = artist.replace("(u", "")
    else:
        artist = "'unknown'"

    artist = (artist.replace("'",""))

    playing = (artist + " - " + title + "             ")
    return playing

#save playing to file.txt

相关qna：

---

为什么它不能解决我的问题：我想打印/保存实际字符，而不是用类似的字符替换它

您得到的错误不是关于unicode，而是关于错误的类型。Python抱怨您试图从数组对象调用string方法

encode

。没有这个方法

我要尝试的第一个方法是删除这里多余的括号，它得到的artiststr如下：

artiststr=str（metadata['xesam:artist']）

---

但我不确定这是否有效。如果它不起作用，您需要找出元数据的类型['xesam:artist']。看起来不是字符串，而是数组。因此，您需要修复用数据填充

元数据['xesam:artist']

的代码。您可以尝试使用调试器或只使用

print（）

函数查找

元数据['xesam:artist']

的内容。或者在您的问题中也提供相关代码。

最终程序，如果您愿意，请随意使用：

import time
import dbus
session_bus = dbus.SessionBus()
spotify_bus = session_bus.get_object("org.mpris.MediaPlayer2.spotify", "/org/mpris/MediaPlayer2")
spotify_properties = dbus.Interface(spotify_bus, "org.freedesktop.DBus.Properties")


def currentplaying():
    metadata = spotify_properties.Get("org.mpris.MediaPlayer2.Player", "Metadata")
    title =  str((metadata['xesam:title']).encode('utf-8'))
    artiststr = str((metadata['xesam:artist'])[0].encode('utf-8'))

    artist = artiststr



    playing = (artist + " - " + title + "             ")
    return playing

while True:

    filetxt = open("/home/USER/Desktop/currentsongspotify.txt", "r")
    oldtitle = filetxt.read()
    filetxt.close()

    newtitle = str(currentplaying())


    if(newtitle == oldtitle):
        time.sleep(1)
    else:
        filetxt = open("/home/USER/Desktop/currentsongspotify.txt", "w")    #save newtitle to file, overwriting existing data
        filetxt.write(str(newtitle))
        print("new file saved:  " + newtitle)

---

查看您的问题

元数据

至少包含类似Unicode字符串的内容。艺术家的领域似乎是某种不可分割的，从艺术家开始。类似这样的内容（可以随意发布实际的元数据内容）：

在

title

赋值行中，

str

是不必要的，因为编码Unicode字符串会返回

str

，但也不需要对其进行编码。Unicode字符串表示文本，因此请保持这种方式：

title =  metadata['xesam:title']

类似于

artist

赋值，但获取iterable的第一个元素：

artist = metadata['xesam:artist'][0]

接下来，在歌曲更新逻辑中，使用

io.open

以UTF-8编码打开文件。这允许直接写入Unicode字符串（文本），文件将处理编码。还可以使用

with

语句在

with

结束时自动关闭文件

带有建议更改的程序：

import time
import dbus
import io
session_bus = dbus.SessionBus()
spotify_bus = session_bus.get_object("org.mpris.MediaPlayer2.spotify", "/org/mpris/MediaPlayer2")
spotify_properties = dbus.Interface(spotify_bus, "org.freedesktop.DBus.Properties")

def currentplaying():
    metadata = spotify_properties.Get("org.mpris.MediaPlayer2.Player", "Metadata")
    title =  metadata['xesam:title']
    artist = metadata['xesam:artist'][0]
    playing = artist + " - " + title + "             "
    return playing

while True:
    with io.open('currentsongspotify.txt', encoding='utf8') as filetxt:
        oldtitle = filetxt.read()
    newtitle = currentplaying()
    if newtitle == oldtitle:
        time.sleep(1)
    else:
        with io.open('currentsongspotify.txt','w',encoding='utf8') as filetxt: # save newtitle to file, overwriting existing data
            filetxt.write(newtitle)
        print 'new file saved:',newtitle

---

python版本：2.7.11感谢您的帮助，有了您的信息，我可以进行简单的重新编码以使其正常工作。非常感谢你。最终的解决方案是：artiststr=str（（元数据['xesam:artist']）[0]。编码（'utf-8'））没有问题。：）是的，它可以工作，但是您应该确保数据集中不会有超过一个项目。

import time
import dbus
import io
session_bus = dbus.SessionBus()
spotify_bus = session_bus.get_object("org.mpris.MediaPlayer2.spotify", "/org/mpris/MediaPlayer2")
spotify_properties = dbus.Interface(spotify_bus, "org.freedesktop.DBus.Properties")

def currentplaying():
    metadata = spotify_properties.Get("org.mpris.MediaPlayer2.Player", "Metadata")
    title =  metadata['xesam:title']
    artist = metadata['xesam:artist'][0]
    playing = artist + " - " + title + "             "
    return playing

while True:
    with io.open('currentsongspotify.txt', encoding='utf8') as filetxt:
        oldtitle = filetxt.read()
    newtitle = currentplaying()
    if newtitle == oldtitle:
        time.sleep(1)
    else:
        with io.open('currentsongspotify.txt','w',encoding='utf8') as filetxt: # save newtitle to file, overwriting existing data
            filetxt.write(newtitle)
        print 'new file saved:',newtitle