Python3中的urlib用法
我得到以下错误:Python3中的urlib用法,python,python-3.x,urllib3,Python,Python 3.x,Urllib3,我得到以下错误: TypeError: POST data should be bytes, an iterable of bytes, or a file object. It cannot be of type str. 在下面打电话时 import urllib.request, urllib.parse, urllib.error, urllib.request, urllib.error, urllib.parse import json chemcalcURL = 'http:
TypeError: POST data should be bytes, an iterable of bytes, or a file object. It cannot be of type str.
在下面打电话时
import urllib.request, urllib.parse, urllib.error, urllib.request,
urllib.error, urllib.parse
import json
chemcalcURL = 'http://www.chemcalc.org/chemcalc/em'
# Define a molecular formula string
mfRange = 'C0-100H0-100N0-10O0-10'
# target mass
mass = 300
# Define the parameters and send them to Chemcalc
# other options (mass tolerance, unsaturation, etc.
params = {'mfRange': mfRange,'monoisotopicMass': mass}
response = urllib.request.urlopen(chemcalcURL, urllib.parse.urlencode(params))
# Read the output and convert it from JSON into a Python dictionary
jsondata = response.read()
data = json.loads(jsondata)
print(data)
您必须将请求转换为字节,这涉及使用
bytes()
arguement:
response = urllib.request.urlopen(chemcalcURL, bytes(urllib.parse.urlencode(params), encoding="utf-8")
bytes()
必须采用一种编码,对于网站而言,这种编码几乎总是utf-8