python类。不确定我是否正确链接了函数。当我询问时，程序不打印

下面的代码是更大代码集的一部分。您将看到我在代码下面有一些测试命令。我正在测试，以确保课堂上所有的方法都有效。我的问题是，代码没有打印到指定的位置。任何人都知道我做错了什么。方法是否正确链接到类

多谢各位

   class Score:
# class to hold a running score, from object to parameter
# also to set number of scores that contribute to total of 1

    def __init__(self):
#initalizes the running score and score input accumilators
        self.runScore = 0
        self.scoreInputs = 0

    def updateOne (self, amount):
#updates running score by amount and Score input by 1
        self.runScore += amount
        self.scoreInputs += 1

    def updateMany(self,lst):
#updates running score by the sum of the list and score inputs by the amount of
# items in the list
        self.runScore += sum(lst)
        self.scoreInputs += len(lst)

    def get(self):
#returns the current score based on total amount scored
        return self.runScore
        print(score.runScore)

    def average(self):
        aver = self.runScore // self.scoreInputs
#returns the average of the scores that have contributed to the total socre
        return aver
        print(score.aver)


    agame = Score()
    agame.updateOne(4)
    agame.updateOne(2)
    agame.updateMany([3,5,4,2,8])
    agame.get()
    agame.average()

我的输出

>>> 
>>> 

因为你什么也看不到

更新

因此，我删除了return语句并修复了一些其他错误，现在我有一个错误，这使我认为我没有将方法完全连接到类。但我还在想办法。有什么想法吗

    class Score:
# class to hold a running score, from object to parameter
# also to set number of scores that contribute to total of 1

    def __init__(self):
#initalizes the running score and score input accumilators
        self.runScore = 0
        self.scoreInputs = 0

    def updateOne (self, amount):
#updates running score by amount and Score input by 1
        self.runScore += amount
        self.scoreInputs += 1

    def updateMany(self,lst):
#updates running score by the sum of the list and score inputs by the amount of
# items in the list
        self.runScore += sum(lst)
        self.scoreInputs += len(lst)

    def get(self):
#returns the current score based on total amount scored
        #return self.runScore #debug test possible removal
        print(Score.runScore)

    def average(self):
        aver = self.runScore // self.scoreInputs
#returns the average of the scores that have contributed to the total socre
        #return aver #debug test possible removal
        print(Score.aver)


agame = Score()
agame.updateOne(4)
agame.updateOne(2)
agame.updateMany([3,5,4,2,8])
agame.get()
agame.average()

输出 我有一个错误，如下所示：

    Traceback (most recent call last):
  File "C:\Users\christopher\Desktop\hw2.py", line 37, in <module>
    agame.get()
  File "C:\Users\christopher\Desktop\hw2.py", line 24, in get
    print(Score.runScore)
AttributeError: type object 'Score' has no attribute 'runScore'

回溯（最近一次呼叫最后一次）：
文件“C:\Users\christopher\Desktop\hw2.py”，第37行，在
阿加梅
get中第24行的文件“C:\Users\christopher\Desktop\hw2.py”
打印（Score.runScore）
AttributeError:类型对象“Score”没有属性“runScore”

打印语句必须在返回语句之前。返回后，程序将退出该功能。

A

return

语句类似于

break

；返回所需变量后，退出上述函数

def foo():
    return 'bar'
    print 'foobar'

---

因此，您需要将

打印

s移到

返回

s之前：

class Score:

# class to hold a running score, from object to parameter
# also to set number of scores that contribute to total of 1

def __init__(self):
#initalizes the running score and score input accumilators

    self.runScore = 0
    self.scoreInputs = 0

def updateOne (self, amount):
#updates running score by amount and Score input by 1

    self.runScore += amount
    self.scoreInputs += 1

def updateMany(self,lst):
#updates running score by the sum of the list and score inputs by the amount of
# items in the list

    self.runScore += sum(lst)
    self.scoreInputs += len(lst)

def get(self):
#returns the current score based on total amount scored


    print(score.runScore)
    return self.runScore

def average(self):
    aver = self.runScore // self.scoreInputs
#returns the average of the scores that have contributed to the total socre


    print(score.aver)
    return aver


agame = Score()
agame.updateOne(4)
agame.updateOne(2)
agame.updateMany([3,5,4,2,8])
agame.get()
agame.average()

---

关键字

return

离开当前函数调用并返回一个值。 见

---

所以，你应该在函数返回之前完成所有操作，就像C一样。

所以最后一个通牒是不使用返回语句，而是使用打印语句。 并将这些方法与自我（xxx）联系起来，而不是与分数联系起来

---

一切都解决了。谢谢大家

在

get（self）

打印前返回。在

average（self）

中也一样。谢谢@A.J。我已经修复了返回语句。我似乎遇到了方法与类完全连接的问题。我说得对吗？你知道我做错了什么吗？目前正在研究这个问题myself@ChristopherJakob我将开始关注这一点：）

class Score:

# class to hold a running score, from object to parameter
# also to set number of scores that contribute to total of 1

def __init__(self):
#initalizes the running score and score input accumilators

    self.runScore = 0
    self.scoreInputs = 0

def updateOne (self, amount):
#updates running score by amount and Score input by 1

    self.runScore += amount
    self.scoreInputs += 1

def updateMany(self,lst):
#updates running score by the sum of the list and score inputs by the amount of
# items in the list

    self.runScore += sum(lst)
    self.scoreInputs += len(lst)

def get(self):
#returns the current score based on total amount scored


    print(score.runScore)
    return self.runScore

def average(self):
    aver = self.runScore // self.scoreInputs
#returns the average of the scores that have contributed to the total socre


    print(score.aver)
    return aver


agame = Score()
agame.updateOne(4)
agame.updateOne(2)
agame.updateMany([3,5,4,2,8])
agame.get()
agame.average()