Python 将两个日期之间的日期传递回formatday方法

我正在学习Python和Django，正在构建一个作业管理应用程序，我有以下内容，它们都可以正常工作，并在HTML日历上显示作业。它显示开始日期和结束日期，但如果作业超过两天，则日历中会出现间隙，因为没有要显示的与作业相关的日期

我可以通过执行以下操作来获得两者之间的日期：

start = job.start_time
end = job.end_time
between = end - start
for i in range(between.days + 1):
    datesbetween = [start + timedelta(days=i)]

下面是my views.py文件：

class AdminCalendarView(LoginRequiredMixin,PermissionRequiredMixin, ListView):
    model = Job
    template_name = 'jobs/admin_diary.html'
    permission_required = 'jobs.add_job', 'raise_exception=True'

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)

        # use today's date for the calendar
        d = get_date(self.request.GET.get('month', None))


        # Instantiate our calendar class with today's year and date
        cal = AdminCalendar(d.year, d.month)

        jobs = Job.objects.filter(start_time__year=d.year, start_time__month=d.month)

        # Call the formatmonth method, which returns our calendar as a table
        html_cal = cal.formatmonth(jobs, withyear=True)
        context['calendar'] = mark_safe(html_cal)
        context['prev_month'] = prev_month(d)
        context['next_month'] = next_month(d)
        return context

from datetime import datetime, timedelta, date
from calendar import HTMLCalendar
from .models import Job
from django.db.models import Q

class AdminCalendar(HTMLCalendar):

    def __init__(self, year=None, month=None):
        self.year = year
        self.month = month
        super(AdminCalendar, self).__init__()

    # formats a day as a td
    # filter jobs by day

    def formatday(self, day, jobs):
        jobs_per_day = jobs.filter(Q(start_time__day=day) | Q(end_time__day=day))
        
        d = ''
        for job in jobs_per_day:
            d += f"<a href='/job/{job.id}'> <li class='job-diary'> {job.client} Job: {job.id}</li> </a>"

        if day != 0:
            return f"<td><span class='date'>{day}</span><ul> {d} </ul></td>"
        return '<td></td>'

        
    # formats a week as a tr
    def formatweek(self, theweek, jobs):
        week = ''
        i = [a_tuple[0] for a_tuple in theweek]
        for d in i:
            week += self.formatday(d, jobs)
        return f'<tr> {week} </tr>'


    # formats a month as a table
    # filter jobs by year and month
    def formatmonth(self, jobs, withyear=True):
        cal = f'<table border="0" cellpadding="0" cellspacing="0" class="calendar table-responsive">\n'
        cal += f'{self.formatmonthname(self.year, self.month, withyear=withyear)}\n'
        cal += f'{self.formatweekheader()}\n'
        for week in self.monthdays2calendar(self.year, self.month):
            cal += f'{self.formatweek(week, jobs)}\n'
        cal += f'</table>'
        return cal

utils.py文件：

class AdminCalendarView(LoginRequiredMixin,PermissionRequiredMixin, ListView):
    model = Job
    template_name = 'jobs/admin_diary.html'
    permission_required = 'jobs.add_job', 'raise_exception=True'

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)

        # use today's date for the calendar
        d = get_date(self.request.GET.get('month', None))


        # Instantiate our calendar class with today's year and date
        cal = AdminCalendar(d.year, d.month)

        jobs = Job.objects.filter(start_time__year=d.year, start_time__month=d.month)

        # Call the formatmonth method, which returns our calendar as a table
        html_cal = cal.formatmonth(jobs, withyear=True)
        context['calendar'] = mark_safe(html_cal)
        context['prev_month'] = prev_month(d)
        context['next_month'] = next_month(d)
        return context

from datetime import datetime, timedelta, date
from calendar import HTMLCalendar
from .models import Job
from django.db.models import Q

class AdminCalendar(HTMLCalendar):

    def __init__(self, year=None, month=None):
        self.year = year
        self.month = month
        super(AdminCalendar, self).__init__()

    # formats a day as a td
    # filter jobs by day

    def formatday(self, day, jobs):
        jobs_per_day = jobs.filter(Q(start_time__day=day) | Q(end_time__day=day))
        
        d = ''
        for job in jobs_per_day:
            d += f"<a href='/job/{job.id}'> <li class='job-diary'> {job.client} Job: {job.id}</li> </a>"

        if day != 0:
            return f"<td><span class='date'>{day}</span><ul> {d} </ul></td>"
        return '<td></td>'

        
    # formats a week as a tr
    def formatweek(self, theweek, jobs):
        week = ''
        i = [a_tuple[0] for a_tuple in theweek]
        for d in i:
            week += self.formatday(d, jobs)
        return f'<tr> {week} </tr>'


    # formats a month as a table
    # filter jobs by year and month
    def formatmonth(self, jobs, withyear=True):
        cal = f'<table border="0" cellpadding="0" cellspacing="0" class="calendar table-responsive">\n'
        cal += f'{self.formatmonthname(self.year, self.month, withyear=withyear)}\n'
        cal += f'{self.formatweekheader()}\n'
        for week in self.monthdays2calendar(self.year, self.month):
            cal += f'{self.formatweek(week, jobs)}\n'
        cal += f'</table>'
        return cal

从datetime导入datetime、timedelta、date
从日历导入HTMLCalendar
从。模型导入作业
从django.db.models导入Q
类管理员日历（HTMLCalendar）：
定义初始（自我，年=无，月=无）：
self.year=年
self.month=月
超级（AdminCalendar，self）。\uuuu init\uuuuu（）
#将一天的格式设置为td
#按天筛选作业
def formatday（自我、日、作业）：
jobs_per_day=jobs.filter（Q（开始时间_day=day）| Q（结束时间_day=day））
d=“”
对于每天作业中的作业：
d+=f“”
如果有一天0:
返回f“{day}
{d}
”
返回“”
#将一周的格式设置为tr
def formatweek（自我、每周、作业）：
周=“”
i=[a_tuple[0]表示一周中的a_tuple]
对于i中的d：
周+=自我形成日（d，作业）
返回f'{week}'
#将月份格式化为表格
#按年度和月份筛选作业
def formatmonth（self，jobs，withyear=True）：
cal=f'\n'
cal+=f'{self.formatmonthname（self.year，self.month，withyear=withyear）}\n'
cal+=f'{self.formatweekheader（）}\n'
对于self.monthdays2日历中的周（self.year，self.month）：
cal+=f'{self.formatweek（week，jobs）}\n'
cal+=f''
返回cal

然而，我不确定我需要如何将这些日子传递回formatday（）方法，或者如果我应该寻找一种不同的方法来完成它，因为这对我来说是全新的，任何帮助都将不胜感激

---

谢谢

在您的

formatday

功能中，您可以通过执行以下操作来筛选介于开始日期和结束日期（包括这些日期）之间的作业：

def formatday(self, day, jobs):
    jobs_per_day = jobs.filter(start_time__day__gte=day, end_time__day__lte=day)

---

这将为您提供从开始到结束的任意天数的作业，包括开始和结束。然后，当前代码将在作业跨越的任何一天显示作业。我相信这就是您所要求的，但如果没有，请随时澄清。

谢谢@joed4no，是的，这正是我想要的，但是我尝试了上述操作，它返回了一个空查询集？