Python 如何在列表中从x删除到y？

我想知道如何从索引x到y删除多个值， 这就是我目前正在尝试的：

first_num = None
second_num = None
while True:
   first_or_last = "first" if first_num is None else "last"
   text = str("Enter the {} index number to start deleting: ").format(first_or_last)
   remove_ftl_input = input(text)
   if first_num is None or second_num is None:
      if remove_ftl_input.isdigit():
         if first_num is None:
            first_num = int(remove_ftl_input)
      elif first_num is not None and second_num is None:
            second_num = int(remove_ftl_input)
      if first_num is not None and second_num is not None:
         for x in range(0, first_num-second_num):
            try:
               # note: every loop index shifts by -1 thats why first-num i assume?
               found_items_list.pop(first_num)
            except IndexError:
               print(str(x) + " was out of reach.")

如何从索引x中删除多个值

为什么不加入你想要保留的范围呢

>>> list = [0, 1, 2, 3, 4, 5, 6, 7]
>>> first = 3
>>> last = 4
>>> list = list[:first] + list[last+1:]
>>> list
[0, 1, 2, 5, 6, 7]

---

您想删除索引

x

中的一个数字并将其放入索引

y

？您可以在迭代列表时从列表中删除元素，只要从右向左操作即可。删除最右边的项不会更改其余项的索引<代码>用于反转的x（范围（0，第一个数值-第二个数值））应该工作：