Python 我得到“要解包的多个值出错，期望值为1”

当我使用search if语句时，我得到一个错误。要解压缩的多个值应为1。我该怎么做我已经试着改变了。谢谢你的建议。我刚开始编码，所以请对我放松点。谢谢

 #Map
 contacts = {}
 #Intro
 print("Address book to store friends contact")
 print("-" * 50)
 print("-" * 50)
 while True:
 #Display of options
     print("Select an option: ")
     print("1-Add/Update contact")
     print("2- Display all contacts")
     print("3- Search")
     print("4- Delete contact")
     print("5- Quit")

     #Selection
     option = input("Select which one you would like to choose. Ex. Select an option. Type here:  ")


  #Main program

     if option == "Add/Update contact":
         person_added = input("Who would you like to be updated or added")
         next_question = input("What is there contact information")
    #The code below will add the person to the list or update them
         contacts[person_added] = next_question

     elif option == "Display all contacts":
         print(contacts)
         print("-" * 50)
         print(" " * 50)

     elif option == "Search":
         search_question = str(input("Who are you looking for: "))
         for search in contacts.items():
             if search == str(search_question):
                 print("I found" + search)
             else:
                 print("Contact not found")

     elif option == "Delete contact":
          person_deleted = input("Who would you like to be deleted ")
         del(contacts[person_deleted])
         print("I just deleted " + person_deleted)

     else:
          print("Thank You for using ME! Goodbye")
          break

这里有一个问题。.items方法返回成对的键和值，因此在第一个print语句中向字符串添加搜索将导致问题。此外，代码有点低效，我们还可以解决：

search_question = input("Who are you looking for: ")
if search_question in contacts:
    print("I found" + search_question)
else:
    print("Contact not found")

---

input已经返回了一个字符串，因此我们不需要尝试使用str来转换它。此外，如果b是字典，那么b中的a将返回a是否是b的键，这正是我们所希望的行为。

如果您在此处发布完整错误，将有所帮助。Python错误提供了很多信息，比如在contacts.items中搜索时出现错误的确切行和位置：-是有问题的行。items返回一对密钥，值请将完整的错误回溯添加到您的问题中！我知道了谢谢你的帮助！请发布你的答案，没有什么比发现有同样问题的人在没有答案的情况下说“我解决了”更令人沮丧的了

search_question = input("Who are you looking for: ")
if search_question in contacts:
    print("I found" + search_question)
else:
    print("Contact not found")