Python 总结列表中的信息

假设我有一个列表：

INPUT=[{'id': 1, 'context': 'this is q1', 'content': 'this is ch1'},
{'id': 1, 'context': 'this is q1', 'content': 'this is ch2'},
{'id': 1, 'context': 'this is q1', 'content': 'this is ch3'}, 
{'id': 2, 'context': 'this is q12', 'content': 'this is ch14'}]

转换：

OUTPUT=[{'id': 1, 'context': 'this is q1', 'content': ['this is ch1','this is ch2','this is ch3']},

{'id': 2, 'context': 'this is q12', 'content': 'this is ch14'}]

python上执行上述转换的最简单方法是什么？

使用itertools.groupby

演示：

输出：

---

我建议您使用以下简短易读的解决方案：

from collections import defaultdict

INPUT=[
    {'id': 1, 'context': 'this is q1', 'content': 'this is ch1'},
    {'id': 1, 'context': 'this is q1', 'content': 'this is ch2'},
    {'id': 1, 'context': 'this is q1', 'content': 'this is ch3'}, 
    {'id': 2, 'context': 'this is q12', 'content': 'this is ch14'}]

# Create first a dictionary:
#     - with tuples (id,context) as key
#     - with the appended contents as value
newDict = defaultdict(list)
for d in INPUT:
    newDict[(d['id'],d['context'])].append(d['content'])

# Convert this dictionary into a list of dictionaries with expected keys
OUTPUT = [{'id':k[0], 'context':k[1], 'content':v} for k,v in newDict.items()]

print(OUTPUT)
# [{'id': 1, 'context': 'this is q1', 'content': ['this is ch1', 'this is ch2', 'this is ch3']},
#  {'id': 2, 'context': 'this is q12', 'content': ['this is ch14']}]

试试这个

for i in range(len(INPUT)):
    INPUT[i]['content'] = [INPUT[i]['content']]
    print(INPUT[i]['content'])

---

上面的转换是什么？你的问题是什么一点也不清楚。这里发生了什么一点也不清楚。您似乎在第一本词典内容的列表中按“这是ch14”列出所有内容。这就是你的意思吗？或者你是在试图把字典的列表合并在一起以形成内容？这个问题提供了多种方法来合并字典中的列表：请澄清您的具体问题或添加额外的详细信息，以突出您所需要的内容。您需要尝试更详细地解释您需要实现的内容。看看这里如何问一个好问题

from collections import defaultdict

INPUT=[
    {'id': 1, 'context': 'this is q1', 'content': 'this is ch1'},
    {'id': 1, 'context': 'this is q1', 'content': 'this is ch2'},
    {'id': 1, 'context': 'this is q1', 'content': 'this is ch3'}, 
    {'id': 2, 'context': 'this is q12', 'content': 'this is ch14'}]

# Create first a dictionary:
#     - with tuples (id,context) as key
#     - with the appended contents as value
newDict = defaultdict(list)
for d in INPUT:
    newDict[(d['id'],d['context'])].append(d['content'])

# Convert this dictionary into a list of dictionaries with expected keys
OUTPUT = [{'id':k[0], 'context':k[1], 'content':v} for k,v in newDict.items()]

print(OUTPUT)
# [{'id': 1, 'context': 'this is q1', 'content': ['this is ch1', 'this is ch2', 'this is ch3']},
#  {'id': 2, 'context': 'this is q12', 'content': ['this is ch14']}]

for i in range(len(INPUT)):
    INPUT[i]['content'] = [INPUT[i]['content']]
    print(INPUT[i]['content'])