Python 如何从两个列表创建嵌套字典？

我有两份清单：

ramp_versions=['RAMPS_1_6','RAMPS_10','RAMPS_11','RAMPS_7','RAMPS_8_9']
columns=['Version','Date','Total_Ramps','Virtual_Ramps','Real_Ramps','Real_Ramps_With_All_Measurements','Real_Ramps_Unsurveyable','Real_Ramps_Partial_With_999','Real_Ramps_Partial_WO_999','Real_Ramps_Partial_W_RAMP_WIDTH_<36_or_DWS_BAD']

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使用听写理解：

{ver: {col: "value" for col in columns} for ver in ramp_versions}

输出：

另一个版本：

nest = {}
for r in ramp_versions:
   nest[r] = dict(zip(columns, ['val' for x in columns]))

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只需对键运行一个循环，并在一个空的定义字典中为其设置值

请参见以下示例：

ramp_versions=['RAMPS_1_6','RAMPS_10','RAMPS_11','RAMPS_7','RAMPS_8_9']
columns=['Version','Date','Total_Ramps','Virtual_Ramps','Real_Ramps','Real_Ramps_With_All_Measurements','Real_Ramps_Unsurveyable','Real_Ramps_Partial_With_999','Real_Ramps_Partial_WO_999','Real_Ramps_Partial_W_RAMP_WIDTH_<36_or_DWS_BAD']

my_dict = {}

i=0
for ramp in ramp_versions:
    my_dict[ramp] = columns[i]
    i+=1

print(my_dict)
# print(my_dict.keys())
# print(my_dict.values())

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你试过什么？你被卡在哪里了？好的，就是这样…我不知道你可以在另一个列表理解中做列表理解

nest = {}
for r in ramp_versions:
   nest[r] = dict(zip(columns, ['val' for x in columns]))

ramp_versions=['RAMPS_1_6','RAMPS_10','RAMPS_11','RAMPS_7','RAMPS_8_9']
columns=['Version','Date','Total_Ramps','Virtual_Ramps','Real_Ramps','Real_Ramps_With_All_Measurements','Real_Ramps_Unsurveyable','Real_Ramps_Partial_With_999','Real_Ramps_Partial_WO_999','Real_Ramps_Partial_W_RAMP_WIDTH_<36_or_DWS_BAD']

my_dict = {}

i=0
for ramp in ramp_versions:
    my_dict[ramp] = columns[i]
    i+=1

print(my_dict)
# print(my_dict.keys())
# print(my_dict.values())