python，tweepy:urllib2.HTTPError:HTTP错误403:禁止

我正在编写一个Twitter应用程序，并试图使用tweepy进行授权。 我遇到了以下错误，无法找出原因

谁能帮我一下吗？我将不胜感激

Traceback (most recent call last):
File "getconv.py", line 32, in <module>
auth=AppAuthHandler(consumer_token,consumer_secret)
File "getconv.py", line 25, in __init__
response=urllib2.urlopen(req,data)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 400, in open
response = meth(req, response)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 513, in http_response
'http', request, response, code, msg, hdrs)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 432, in error
result = self._call_chain(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 372, in _call_chain
result = func(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 619, in http_error_302
return self.parent.open(new, timeout=req.timeout)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 400, in open
response = meth(req, response)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 513, in http_response
'http', request, response, code, msg, hdrs)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 438, in error
return self._call_chain(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 372, in _call_chain
result = func(*args)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib2.py", line 521, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 403: Forbidden

---

该错误与tweepy无关，它来自您的自定义

AppAuthHandler

：

>>> auth = AppAuthHandler(TWITTER_CONSUMER_KEY, TWITTER_CONSUMER_SECRET)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 403: Forbidden

演示：

>>AppAuthHandler（TWITTER\u消费者密钥，TWITTER\u消费者密钥）

您的问题标题有点误导，因为（假设您的身份验证信息是正确的）这似乎是tweepy的问题。另一方面，您的头意味着使用urllib2时出现问题directly@AndreasKlebinger我现在还不能确定错误是来自urllib2还是tweepy。不管怎样，我在标题上加了tweepy。非常感谢你的回答。现在，在您的帮助下，代码本身可以工作，但我仍然得到错误的身份验证数据：代码215错误。。身份验证后，我将通过url=“然后tweetdata=urlib2.urlopen（url）.read（）调用url。您能帮我找出原因吗？@CosmicRabbitMediaInc出于好奇，为什么不

api=tweepy.api（auth）

，

api.

？以及什么端点

”api.twitter.com/1.1/search/show.json？id=

你认为是吗？是1.0版的链接吗？我不知道你说的是什么意思。。上面url的结果只是“{”错误“：[{”消息“：“错误的身份验证数据”，“代码“：215}]}”，没有对1.0的引用

>>> auth = AppAuthHandler(TWITTER_CONSUMER_KEY, TWITTER_CONSUMER_SECRET)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
    raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 403: Forbidden

class AppAuthHandler(tweepy.auth.AuthHandler):
    TOKEN_URL='https://api.twitter.com/oauth2/token'
    def __init__(self,consumer_key,consumer_secret):
        token_credential = '{}:{}'.format(*map(urllib.quote, [consumer_key, consumer_secret]))
        credential = base64.b64encode(token_credential)
        value = {'grant_type': 'client_credentials'}
        data = urllib.urlencode(value)
        req = urllib2.Request(self.TOKEN_URL)
        req.add_header('Authorization', 'Basic {}'.format(credential))
        req.add_header('Content-Type', 'application/x-www-form-urlencoded;charset=UTF-8')
        response=urllib2.urlopen(req, data)
        json_response=json.loads(response.read())
        self._access_token=json_response['access_token']
    def apply_auth(self,url,method,headers,parameters):
        headers['Authorization'] = 'Bearer {}'.format(self._access_token)

>>> AppAuthHandler(TWITTER_CONSUMER_KEY, TWITTER_CONSUMER_SECRET)
<__main__.AppAuthHandler object at 0x11b7d10>