python：从csv拆分并创建json数据

如何创建从csv到json的嵌套字段？我查看了另一个stackoverflow，但它们并不是我想要格式化的。我有一个包含1列的数据集，必须将其转换为嵌套字段

数据：

代码：

with open('test.csv', 'r') as file:
            headers = next(file) #skip the headers
            fieldnames = headers.rstrip().split(",")
            csv_reader = csv.DictReader(file, fieldnames) #creating a dictionary
            import datetime
            for row_dict in csv_reader:
                row_dict['name'] = row_dict['name'].split(",")
                json_data = json.dumps(row_dict)
                print(json_data)

我正在列表中获取输出，但它不是嵌套的

{"id": "1", "name": ["Smith", " Mr. Adams"]}
{"id": "2", "name": ["McAdams", " Mrs. Audrey"]}
{"id": "3", "name": ["McAdams", " Doctor John"]}
{"id": "4", "name": ["Missing Value"]}

最终输出：有没有办法做到这一点

{"id": "1", "name": [{"last_name": "Smith",
                      "prefix": "Mr.",
                      "first_name":  "Adams"}]}
{"id": "1", "name": [{"last_name": "McAdams",
                      "prefix": "Mrs.",
                      "first_name":  "Audrey"}]}
{"id": "1", "name": [{"last_name": "McAdams",
                      "prefix": "Dr.",
                      "first_name":  "John"}]}
{"id": "1", "name": [{"last_name": "Missing Value",
                      "prefix": "Missing Value",
                      "first_name":  "Missing Value"}]}                   

只需使用。拆分一些时间并创建一个新的dict

import json

csv = '''1, "Smith, Mr. Adams"
2, "McAdams, Mrs. Audrey"
3, "McAdams, Doctor John"
4, "Missing Value"'''

csv_lines = csv.split('\n')


for line in csv_lines:
  id = line.split(',')[0]
  name = line[len(id)+3:-1]
  split = name.split(', ')
  last_name = split[0]
  if len(split) < 2:
    first_name = last_name
    prefix = last_name
  else:
    prefix = split[1].split(' ')[0]
    first_name = split[1][len(prefix)+1:]

  row_dict = {'id': id, 'name': {'last_name': last_name, 'prefix': prefix, 'first_name': first_name}}

  json_data = json.dumps(row_dict)
  print(json_data)

---

为什么您想要的结果中的名称条目是一个字典列表，而不仅仅是一个字典？您需要编写一个函数，将名称解析到您想要的字典中。不能只使用split，因为这不会提取前缀，也不会将缺少的值放入所有缺少的字段中。名称有许多不同的格式，因此这可能会很复杂，并且在处理不当的情况下会产生错误。这就是为什么表单通常对名字、姓氏、标题等有单独的输入字段。对于最终输出，请查看此项。我现在正在使用它，虽然不完美，但肯定比从头开始实现要好。如果名称dict确实必须在列表中，您可以通过更改创建行dict的行来实现它。

import json

csv = '''1, "Smith, Mr. Adams"
2, "McAdams, Mrs. Audrey"
3, "McAdams, Doctor John"
4, "Missing Value"'''

csv_lines = csv.split('\n')


for line in csv_lines:
  id = line.split(',')[0]
  name = line[len(id)+3:-1]
  split = name.split(', ')
  last_name = split[0]
  if len(split) < 2:
    first_name = last_name
    prefix = last_name
  else:
    prefix = split[1].split(' ')[0]
    first_name = split[1][len(prefix)+1:]

  row_dict = {'id': id, 'name': {'last_name': last_name, 'prefix': prefix, 'first_name': first_name}}

  json_data = json.dumps(row_dict)
  print(json_data)

{"id": "1", "name": {"last_name": "Smith", "prefix": "Mr.", "first_name": "Adams"}}
{"id": "2", "name": {"last_name": "McAdams", "prefix": "Mrs.", "first_name": "Audrey"}}
{"id": "3", "name": {"last_name": "McAdams", "prefix": "Doctor", "first_name": "John"}}
{"id": "4", "name": {"last_name": "Missing Value", "prefix": "Missing Value", "first_name": "Missing Value"}}