Python 关于继承以前模式的意见
我正在查看我的代码,看到这两个模型有多个相似的字段。我想知道我的ParentProfile模型是否可以继承我的用户模型以缩短代码并消除重叠。这是一个相当初级的问题,我想听听其他人对这件事的看法。谢谢大家! models.pyPython 关于继承以前模式的意见,python,django,inheritance,model,Python,Django,Inheritance,Model,我正在查看我的代码,看到这两个模型有多个相似的字段。我想知道我的ParentProfile模型是否可以继承我的用户模型以缩短代码并消除重叠。这是一个相当初级的问题,我想听听其他人对这件事的看法。谢谢大家! models.py class User(AbstractBaseUser): email = models.EmailField(max_length=255, unique=True) first_name = models.CharField(max_length=255
class User(AbstractBaseUser):
email = models.EmailField(max_length=255, unique=True)
first_name = models.CharField(max_length=255)
last_name = models.CharField(max_length=255)
child_first_name = models.CharField(max_length=255)
timestamp = models.DateTimeField(auto_now_add=True)
student = models.BooleanField(default=False)
parent = models.BooleanField(default=False)
teacher = models.BooleanField(default=False)
active = models.BooleanField(default=True) # can login
staff = models.BooleanField(default=False) # staff user, not superuser
admin = models.BooleanField(default=False) # superuser
objects = UserManager()
# takes email as username | removes email
USERNAME_FIELD = 'email'
REQUIRED_FIELDS = ['first_name', 'last_name']
def __str__(self):
return self.email
def has_perm(self, perm, onj=None):
"Does the user have a specific permission?"
return True
def has_module_perms(self, app_label):
"Does the user have permissions to view the app 'app_label'?"
return True
@property
def is_staff(self):
return self.staff
@property
def is_admin(self):
return self.admin
@property
def is_active(self):
return self.active
class ParentProfile(models.Model):
user = models.OneToOneField(User, on_delete=models.CASCADE)
email = models.EmailField(max_length=255, unique=True)
first_name = models.CharField(max_length=255)
last_name = models.CharField(max_length=255)
child_first_name = models.CharField(max_length=255)
timestamp = models.DateTimeField(auto_now_add=True)
student = models.BooleanField(default=False)
parent = models.BooleanField(default=False)
teacher = models.BooleanField(default=False)
active = models.BooleanField(default=True) # can login
staff = models.BooleanField(default=False) # staff user, not superuser
admin = models.BooleanField(default=False) # superuser
objects = UserManager()
# takes email as username | removes email
USERNAME_FIELD = 'email'
REQUIRED_FIELDS = ['first_name', 'last_name', 'child_first_name']
def __str__(self):
return self.email
def has_perm(self, perm, onj=None):
"Does the user have a specific permission?"
return True
def has_module_perms(self, app_label):
"Does the user have permissions to view the app 'app_label'?"
return True
@property
def is_staff(self):
return self.staff
@property
def is_admin(self):
return self.admin
@property
def is_active(self):
return self.active
您可以使用commons字段创建抽象模型,并在这两个字段中进行继承
class CommonFieldModel(models.Model):
email = models.EmailField(max_length=255, unique=True)
first_name = models.CharField(max_length=255)
last_name = models.CharField(max_length=255)
child_first_name = models.CharField(max_length=255)
timestamp = models.DateTimeField(auto_now_add=True)
student = models.BooleanField(default=False)
parent = models.BooleanField(default=False)
teacher = models.BooleanField(default=False)
active = models.BooleanField(default=True) # can login
staff = models.BooleanField(default=False) # staff user, not superuser
admin = models.BooleanField(default=False) # superuser
class Meta:
abstract = True
正如Meta
类所定义的,它是一个抽象模型,Django不会为此创建任何表。现在,您可以在其他模型中继承此模型。前
class ParentProfile(CommonFieldModel):
user = models.OneToOneField(User, on_delete=models.CASCADE)
class User(CommonFieldModel, AbstractBaseUser):
user = models.OneToOneField(User, on_delete=models.CASCADE)
为什么在第一个地方有两个相同的模型?第二个模型有一个额外的字段。继承第一个模型并简单地在额外字段中添加child_first_name=models.CharField(max_length=255)与获取第一个模型的所有函数一样有效。或者我应该在表单中添加一个额外的字段,然后废弃整个模型吗