Python字典输出问题

我不熟悉python和这个论坛。在线学习对我不起作用，所以我不能只去找家教。可能是我忘记了一些小事。我欢迎你给我任何帮助

我试图让输出看起来像这样：她的名字是埃米洛；她有望在2021年秋季毕业；她的账单付清了；她的专业是考古学；她属于这些学校俱乐部——摄影、表演和欢乐合唱团

Emm = {'name' : 'Emmylou', 'graduate' : 'Fall 2021', 'bill' : 'paid', 'major' : 'Archeology', 'clubs-' : 'Photography, Acting and Glee'}

for Key, Value in Emm.items():

print(f"Her {Key} is {Value} and she is on track to {Key} in {Value}; Her {Key} is {Value}; Her {Key} is {Value}; She belongs to these school {Key} {Value}")

输出非常混乱，在我运行它时如下所示：

Her name is Emmylou and she is on track to name in Emmylou; Her name is Emmylou; Her name is Emmylou; She belongs to these school name Emmylou
Her graduate is Fall 2021 and she is on track to graduate in Fall 2021; Her graduate is Fall 2021; Her graduate is Fall 2021; She belongs to these school graduate Fall 2021
Her bill is paid and she is on track to bill in paid; Her bill is paid; Her bill is paid; She belongs to these school bill paid
Her major is Archeology and she is on track to major in Archeology; Her major is Archeology; Her major is Archeology; She belongs to these school major Archeology
Her clubs- is Photography, Acting and Glee and she is on track to clubs- in Photography, Acting and Glee; Her clubs- is Photography, Acting and Glee; Her clubs- is Photography, Acting and Glee; She belongs to these school clubs- Photography, Acting and Glee

---

在代码中，迭代数据中的每个键值对；因此，您最终打印了5次，每次使用一个键值对，而不是使用所有键值对打印1次

试试这个

Emm = [
    ('name', 'Emmylou'),
    ('graduate', 'Fall 2021'),
    ('bill', 'paid'),
    ('major', 'Archeology'),
    ('clubs-', 'Photography, Acting and Glee'),
]

flat_items = [item for pair in Emm for item in pair]
print("Her {} is {} and she is on track to {} in {}; Her {} is {}; Her {} is {}; She belongs to these school {} {}".format(*flat_items))

---

首先，我将假设您实际上已经在代码中缩进了print语句，因为否则它根本不起作用

问题是，对于每个循环，您在所有位置填充相同的键/值对

根据目的，你可以通过以下方式获得陈述：

Emm = {'name' : 'Emmylou', 'graduate' : 'Fall 2021', 'bill' : 'paid', 'major' : 'Archeology', 'clubs-' : 'Photography, Acting and Glee'}
print(f"Her name is {Emm['name']} and she is on track to graduate in {Emm['graduate']}; Her major is {Emm['major']}; Her clubs - is {Emm['clubs-']}")

---

迭代字典可能面临的另一个问题是，除非您使用的是python 3.7或更高版本，否则无法保证在字典中保存项目的顺序。因此，您的键/值对可能不会以它们进入的相同顺序出现。

正如其他人告诉您的那样，您正在迭代字典，在每次迭代中，键和值都会被替换并打印在新的行中

如果要使用字典在单行中打印，可以尝试将字典转换为数组并使用format方法打印

Emm = {
    'name' : 'Emmylou',
    'graduate' : 'Fall 2021',
    'bill' : 'paid',
    'major' : 'Archeology',
    'clubs-' : 'Photography, Acting and Glee'
}

items = []
for (key, value) in Emm.items():
    items = items + [key, value]
print("Her {} is {} and she is on track to {} in {}; Her {} is {}; Her {} is {}; She belongs to these school {} {}".format(*items))

---

因为您知道应该在句子中放置哪个键，所以您可以只执行Emm['key']来获取值，而不是在字典中进行迭代。例如：print（f）“她的名字是Emm['name']，她即将毕业于Emm['graduate']..字典在概念上没有顺序。由于变量的大小写敏感性，您提供的解决方案代码将遇到错误，在print语句中使用了“emm”，但emm中的e需要大写，其次print语句将打印5次，因为这是字典的长度。谢谢@BrendaMejia，我已经根据需要编辑了代码。这里唯一的问题是，对于许多版本的Python，字典键的迭代顺序无法保证。哦，我使用新版本太久了，以至于忘记了这一点。看起来OrderDict可能有点过火，使用元组列表进行更新。这里唯一的问题是，对于许多版本的Python来说Python的迭代不能保证字典键的迭代顺序。