访问python以获取循环值

我正在用Python做一些实验，并试图构建一个刮板。我已经拥有的代码打印在下面

import requests
from bs4 import BeautifulSoup
import csv

url = "http://www.grammy.com/nominees/search"
r = requests.get(url)

soup = BeautifulSoup(r.content)

g_data = soup.find_all("div", {"class": "view-content"})

f = csv.writer(open("file.csv", "w"))
f.writerow(["Year", "Category", "Title", "Winner"])

for item in g_data:
  for year in item.find_all("td", {"class": "views-field-year"}):
    year = year.contents[0]

  for category in item.find_all("td", {"class": "views-field-category-code"}):
    category = category.contents[0]

  for title in item.find_all("td", {"class": "views-field-field-nominee-work"}):
    title = title.contents[0]

  for winner in item.find_all("td", {"class": "views-field-field-nominee-extended"}):
    winner = winner.contents[0]

f.writerow([year, category, title, winner])

---

出于某种原因，CSV文件只有一行，是随机的。我如何才能访问

范围之外的所有这些值？
您的写调用在循环之外，因此您只写了一行（最后一行）。缩进它，它应该按预期工作：

for item in g_data:
  for year in item.find_all("td", {"class": "views-field-year"}):
    year = year.contents[0]

  for category in item.find_all("td", {"class": "views-field-category-code"}):
    category = category.contents[0]

  for title in item.find_all("td", {"class": "views-field-field-nominee-work"}):
    title = title.contents[0]

  for winner in item.find_all("td", {"class": "views-field-field-nominee-extended"}):
    winner = winner.contents[0]

  f.writerow([year, category, title, winner])

如果您是Python新手，代码块是通过缩进来定义的。
不仅仅是您的上一个
writerow（）
没有正确缩进（它应该在循环体下）。此外，您需要迭代
tr
元素（表示包含数据的所需
表中的每一行），为循环中找到的每个
tr
获取
td
元素

我还避免检查循环中
td
元素的
class
属性值，只需通过索引获取它们——换句话说，为每个
tr
查找所有
td
元素，并获取
文本

修正版和改进版（仅2行代码）：

运行代码后，
文件.csv
的内容：

Year,Category,Title,Winner
2014,Record Of The Year,Stay With Me (Darkchild Version),"Sam Smith, artist. Steve Fitzmaurice, Rodney Jerkins & Jimmy Napes, producers. Matthew Champlin, Steve Fitzmaurice, Jimmy Napes & Steve Price, engineers/mixers. Tom Coyne, mastering engineer."
2014,Album Of The Year,Morning Phase,"Beck Hansen, producer; Tom Elmhirst, David Greenbaum, Cole Marsden Greif-Neill, Florian Lagatta, Robbie Nelson, Darrell Thorp, Cassidy Turbin & Joe Visciano, engineers/mixers; Bob Ludwig, mastering engineer."
2014,Song Of The Year,Stay With Me (Darkchild Version),"James Napier, William Phillips &Sam Smith, songwriters."
...
2014,Best Rap Song,I,"K. Duckworth, Ronald Isley & C. Smith, songwriters."
2014,Best Rap Album,The Marshall Mathers LP2,"Eminem, artist. Tony Campana, Joe Strange & Mike Strange, engineers/mixers."

是的，但是如何定义“未定义”字符串。例如：在循环的第一个
中，其他值没有定义Yet将这些字段拆分为独立列的最佳方法是什么？@BobWassermann您能详细说明“将这些字段拆分为独立列”是什么意思吗？现在Python将所有数据放在一列中，如下所示“2014年，最佳乡村独奏表演，水中之物，”艺术家Carrie Underwood。“2014年，最佳乡村独奏…等需要在单独的列中。TLDR；每个
，
应打开一个新列。分隔符“；”已修复。
Year,Category,Title,Winner
2014,Record Of The Year,Stay With Me (Darkchild Version),"Sam Smith, artist. Steve Fitzmaurice, Rodney Jerkins & Jimmy Napes, producers. Matthew Champlin, Steve Fitzmaurice, Jimmy Napes & Steve Price, engineers/mixers. Tom Coyne, mastering engineer."
2014,Album Of The Year,Morning Phase,"Beck Hansen, producer; Tom Elmhirst, David Greenbaum, Cole Marsden Greif-Neill, Florian Lagatta, Robbie Nelson, Darrell Thorp, Cassidy Turbin & Joe Visciano, engineers/mixers; Bob Ludwig, mastering engineer."
2014,Song Of The Year,Stay With Me (Darkchild Version),"James Napier, William Phillips &Sam Smith, songwriters."
...
2014,Best Rap Song,I,"K. Duckworth, Ronald Isley & C. Smith, songwriters."
2014,Best Rap Album,The Marshall Mathers LP2,"Eminem, artist. Tony Campana, Joe Strange & Mike Strange, engineers/mixers."