Python 使用for循环打印时间序列
我想创建一个打印以下内容的循环:Python 使用for循环打印时间序列,python,python-3.x,for-loop,Python,Python 3.x,For Loop,我想创建一个打印以下内容的循环: "The train will leave at 13:36" "The train will leave at 13:56" "The train will leave at 14:16" "The train will leave at 14:36" "The train will leave at 14:56" "The train will leave at 15:16" etc. etc... 我有一个密码,上面写着: h = 13 m = 36
"The train will leave at 13:36"
"The train will leave at 13:56"
"The train will leave at 14:16"
"The train will leave at 14:36"
"The train will leave at 14:56"
"The train will leave at 15:16"
etc. etc...
我有一个密码,上面写着:
h = 13
m = 36
for i in range(5):
print("The train will leave at {}:{} ".format(h,m))
m = m + 20
if 60 <= m:
break
print("The train will leave at {}:{} ".format(h,m))
h = h+1
m = m-60+20
我如何修复它,使分钟增加20分钟,并且每次达到60分钟时,它应该输出正确的时间…用于处理分钟和小时,即模运算符%
和楼层划分/
:
h = 13
m = 36
for i in range(10):
print("The train will leave at {}:{} ".format(h,m))
h = h+((m+20)//60)
m = (m+20)%60
if h == 24:
h = 0
注意最后两行:当h==24
用于处理分钟和小时时,您应该检查小时值以返回到0,即模数运算符%
和楼层划分/
:
h = 13
m = 36
for i in range(10):
print("The train will leave at {}:{} ".format(h,m))
h = h+((m+20)//60)
m = (m+20)%60
if h == 24:
h = 0
注意最后两行:当
h==24
稍微修改代码版本时,您应该检查小时值以返回0。只需使用if
检查分钟数。如果分钟数大于60,则将小时数增加1,并通过减去60将分钟数倒回
h = 13
m = 36
for i in range(5):
if 60 <= m:
m = m-60
h = h+1
print("The train will leave at {}:{} ".format(h,m))
m = m + 20
# The train will leave at 13:36
# The train will leave at 13:56
# The train will leave at 14:16
# The train will leave at 14:36
# The train will leave at 14:56
h=13
m=36
对于范围(5)中的i:
如果60代码有轻微的修改版本。只需使用if
检查分钟数。如果分钟数大于60,则将小时数增加1,并通过减去60将分钟数倒回
h = 13
m = 36
for i in range(5):
if 60 <= m:
m = m-60
h = h+1
print("The train will leave at {}:{} ".format(h,m))
m = m + 20
# The train will leave at 13:36
# The train will leave at 13:56
# The train will leave at 14:16
# The train will leave at 14:36
# The train will leave at 14:56
h=13
m=36
对于范围(5)中的i:
如果60您应该尝试%运算符
运算符是一种很容易理解的运算符,它提供左操作数和右操作数之间除法的剩余部分。如果你在大学里学习过群论或抽象代数,那么定义这个操作符会变得更专业一些
基本上从给定的一分钟开始,增加20分钟。当分钟数超过60分钟时,我们需要增加小时数。但我们需要重置分钟数。所以当m
第一次达到76时,我们将其设置回76-(1*60)=16
。请注意,m
将永远不会超过120,除非从开始设置为大于99的数字
我想你真正想要的是这个
h=13
m=36
对于范围(5)中的i:
打印(“列车将在{}:{}发车”。格式(h,m))
m=m+20
如果m>=60:
h+=1
m=m%60
输出
列车将于13:36发车
#火车将于13:56发车
#火车将于14:16发车
#火车将于14:36发车
#火车将于14:56发车
但您可能还应该说明h
何时超过24。所以如果h>=24:h=0
再次假设您总是从60以下的m开始。您应该尝试%运算符
运算符是一种很容易理解的运算符,它提供左操作数和右操作数之间除法的剩余部分。如果你在大学里学习过群论或抽象代数,那么定义这个操作符会变得更专业一些
基本上从给定的一分钟开始,增加20分钟。当分钟数超过60分钟时,我们需要增加小时数。但我们需要重置分钟数。所以当m
第一次达到76时,我们将其设置回76-(1*60)=16
。请注意,m
将永远不会超过120,除非从开始设置为大于99的数字
我想你真正想要的是这个
h=13
m=36
对于范围(5)中的i:
打印(“列车将在{}:{}发车”。格式(h,m))
m=m+20
如果m>=60:
h+=1
m=m%60
输出
列车将于13:36发车
#火车将于13:56发车
#火车将于14:16发车
#火车将于14:36发车
#火车将于14:56发车
但您可能还应该说明h
何时超过24。所以如果h>=24:h=0
再次假设您总是从60以下的m开始。您可以使用标准库中的
datetime
模块:
from datetime import timedelta, datetime
t = datetime(hour=13, minute=36, year=2019, month=6, day=9)
for i in range(5):
print("The train will leave at {}:{} ".format(t.hour,t.minute))
t += timedelta(minutes=20)
印刷品:
The train will leave at 13:36
The train will leave at 13:56
The train will leave at 14:16
The train will leave at 14:36
The train will leave at 14:56
您可以使用标准库中的
datetime
模块:
from datetime import timedelta, datetime
t = datetime(hour=13, minute=36, year=2019, month=6, day=9)
for i in range(5):
print("The train will leave at {}:{} ".format(t.hour,t.minute))
t += timedelta(minutes=20)
印刷品:
The train will leave at 13:36
The train will leave at 13:56
The train will leave at 14:16
The train will leave at 14:36
The train will leave at 14:56
使用以下if语句检查小时更改,我已更改小时和分钟以进行双重检查
h = 15
m = 53
for i in range(5):
print("The train will leave at {}:{} ".format(h,m))
m = m + 20
if m >= 60:
h = h+1
m-=60
print("The train will leave at {}:{} ".format(h,m))
m = m + 20
执行将是:
The train will leave at 15:53
The train will leave at 16:13
The train will leave at 16:33
The train will leave at 16:53
The train will leave at 17:13
The train will leave at 17:33
The train will leave at 17:53
The train will leave at 18:13
使用以下if语句检查小时更改,我已更改小时和分钟以进行双重检查
h = 15
m = 53
for i in range(5):
print("The train will leave at {}:{} ".format(h,m))
m = m + 20
if m >= 60:
h = h+1
m-=60
print("The train will leave at {}:{} ".format(h,m))
m = m + 20
执行将是:
The train will leave at 15:53
The train will leave at 16:13
The train will leave at 16:33
The train will leave at 16:53
The train will leave at 17:13
The train will leave at 17:33
The train will leave at 17:53
The train will leave at 18:13
使用
divmod
函数使用divmod
函数