Python 使用嵌套字典创建多索引“Series”
在我看来,我试图做的应该是简单的,就像将其传递给构造函数一样简单,但实际上并非如此。我有一本下面这样的字典Python 使用嵌套字典创建多索引“Series”,python,pandas,dictionary,nested,series,Python,Pandas,Dictionary,Nested,Series,在我看来,我试图做的应该是简单的,就像将其传递给构造函数一样简单,但实际上并非如此。我有一本下面这样的字典 d = {"russell": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)}, "cantor": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)}, "godel": {"score": n
d = {"russell": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)},
"cantor": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)},
"godel": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)}}
russell score 0.87391482
ping 23
cantor score 0.77821932
ping 16
godel score 0.53372128
ping 35
我想做一些类似于pandas.Series(d)
的事情,并获得一个Series
实例,如下所示
d = {"russell": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)},
"cantor": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)},
"godel": {"score": numpy.random.rand(), "ping": numpy.random.randint(10, 100)}}
russell score 0.87391482
ping 23
cantor score 0.77821932
ping 16
godel score 0.53372128
ping 35
但我真正得到的是下面
cantor {'ping': 44, 'score': 0.007408727109865398}
godel {'ping': 41, 'score': 0.9338940910283948}
russell {'ping': 74, 'score': 0.733817307366666}
有没有一种方法可以实现我想要实现的目标?我认为您需要具备:
此外,如果需要在多索引中交换级别,请使用: