用python编写了一个非常简单的猜字游戏，每次猜错的时候都会得到提示，但不起作用

唯一的问题是，当你正确地猜出单词时，循环会继续进行，并且不会识别出猜测=秘密的单词。因此，没有办法真正赢得游戏，所有用户都注定要失败。我想这可能是用户如何将信息输入guesses变量的问题，因此guesses变量无法与机密字进行比较，但它似乎写得很好，所以idk。

您的代码工作正常。然而，编程的原则之一是——不要重复你自己

不要像以前那样编写代码，尽量避免重复。这使您的代码易于阅读、理解和调试

您可以使用列表存储要在每个回合打印的消息

secret_word = "Banana"
guesses = ""
maximum_guesses = 5
number_of_guesses = 0
out_of_guesses = False
while guesses != secret_word and not out_of_guesses:
    if number_of_guesses == 0:
        guesses = input("Guess a word: ")
        number_of_guesses += 1
    elif number_of_guesses == 1:
        print("The object is edible")
        guesses = input("Guess again: ")
        number_of_guesses += 1
    elif number_of_guesses == 2:
        print("The object is yellow: ")
        guesses = input("Guess again: ")
        number_of_guesses += 1
    elif number_of_guesses == 3:
        print("The object is a fruit:  ")
        guesses = input("Guess again: ")
        number_of_guesses += 1
    elif number_of_guesses == 4:
        print("You're stupid ")
        guesses = input("Guess again: ")
        number_of_guesses += 1
    else:
        out_of_guesses == True

if out_of_guesses == True:
    print("You have lost")
else:
    print("you have won")

然后，您所需要做的就是使用号码来访问列表中的消息。您还可以使用for循环来跟踪循环是已中断还是已成功结束。 此外，您可能希望比较单词的小写版本，以便您的程序不会认为“banana”和“banana”是不同的单词

secret_word = "banana"
hints = ["", "The object is edible", "The object is yellow", "The object is a fruit", "You're stupid"]
maximum_guesses = len(hints)

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看到了吗？可读性更强，因此很容易判断是否有错误

对我有用。你确定你猜的是“香蕉”而不是“香蕉”或其他什么吗？我本可以要求的最好的反馈，现在我意识到我的干编码，并且已经在考虑其他项目了。非常感谢。

for guess_num in range(maximum_guesses):
    if guess_num == 0:
        guess = input("Guess a word: ")
    else: # Print the hint and guess again for turn 2 onwards
        print(hints[guess_num])
        guess = input("Guess again: ")

    if guess.lower() == secret_word: # If correctly guessed, say so and break the loop
        print("You have won")
        break
else: # Loop wasn't broken, player lost
    print("You have lost")