Python中使用嵌套循环的两位数乘法表
我正在学习嵌套循环,所以我想做一个简单的乘法表,你能帮我改进代码吗Python中使用嵌套循环的两位数乘法表,python,python-2.7,for-loop,nested-loops,Python,Python 2.7,For Loop,Nested Loops,我正在学习嵌套循环,所以我想做一个简单的乘法表,你能帮我改进代码吗 for i in range(1,10): print("i =", i, ":") for j in range(1, 10): print (i*j) 我的程序在运行时看起来非常混乱,如何将结果对齐到矩阵/表格之类的东西中以使其更易于阅读?您想要这样的东西吗?: for i in range(1, 10): print '\n','{:02}'.format(i),':',
for i in range(1,10):
print("i =", i, ":")
for j in range(1, 10):
print (i*j)
我的程序在运行时看起来非常混乱,如何将结果对齐到矩阵/表格之类的东西中以使其更易于阅读?您想要这样的东西吗?:
for i in range(1, 10):
print '\n','{:02}'.format(i),':',
for j in range(1, 10):
print '{:02}'.format(i*j),
[OUTPUT]
01 : 01 02 03 04 05 06 07 08 09
02 : 02 04 06 08 10 12 14 16 18
03 : 03 06 09 12 15 18 21 24 27
04 : 04 08 12 16 20 24 28 32 36
05 : 05 10 15 20 25 30 35 40 45
06 : 06 12 18 24 30 36 42 48 54
07 : 07 14 21 28 35 42 49 56 63
08 : 08 16 24 32 40 48 56 64 72
09 : 09 18 27 36 45 54 63 72 81
或:
如果您使用的是Python2.x,
print
是一条语句,因此需要确保打印当前行后该行不会结束{:2d}
在格式
函数中,确保始终有两位数字的空间。如果您更喜欢0
而不是空格,则可以使用{:02d}
for i in range(1, 10):
print "i =", i, ":", # Note the comma at the end
for j in range(1, 10):
print "{:2d}".format(i * j), # Note the comma at the end
print
输出
i = 1 : 1 2 3 4 5 6 7 8 9
i = 2 : 2 4 6 8 10 12 14 16 18
i = 3 : 3 6 9 12 15 18 21 24 27
i = 4 : 4 8 12 16 20 24 28 32 36
i = 5 : 5 10 15 20 25 30 35 40 45
i = 6 : 6 12 18 24 30 36 42 48 54
i = 7 : 7 14 21 28 35 42 49 56 63
i = 8 : 8 16 24 32 40 48 56 64 72
i = 9 : 9 18 27 36 45 54 63 72 81
在打印
中做一些小改动,也可以使其在Python3.x中工作。请记住,print
是Python 3.x中的一个函数
for i in range(1, 10):
print("i =", i, ":", end=" ")
for j in range(1, 10):
print("{:2d}".format(i * j), end=" ")
print()
注意:您可以在Python文档的一节中阅读有关各种字符串格式选项的更多信息。试试这个
for a in range(1,6):
print(a,'tables')
for b in range(1,11):
c=a*b
print(a,'X',b,'=', c)
print()
Just replace 6 by a number which you want and 1 to that (eg: if you
want up to 10 replace 6 with 11)
输出
1 tables
1 X 1 = 1
1 X 2 = 2
1 X 3 = 3
1 X 4 = 4
1 X 5 = 5
1 X 6 = 6
1 X 7 = 7
1 X 8 = 8
1 X 9 = 9
1 X 10 = 10
2 tables
2 X 1 = 2
2 X 2 = 4
2 X 3 = 6
2 X 4 = 8
2 X 5 = 10
2 X 6 = 12
2 X 7 = 14
2 X 8 = 16
2 X 9 = 18
2 X 10 = 20
3 tables
3 X 1 = 3
3 X 2 = 6
3 X 3 = 9
3 X 4 = 12
3 X 5 = 15
3 X 6 = 18
3 X 7 = 21
3 X 8 = 24
3 X 9 = 27
3 X 10 = 30
4 tables
4 X 1 = 4
4 X 2 = 8
4 X 3 = 12
4 X 4 = 16
4 X 5 = 20
4 X 6 = 24
4 X 7 = 28
4 X 8 = 32
4 X 9 = 36
4 X 10 = 40
5 tables
5 X 1 = 5
5 X 2 = 10
5 X 3 = 15
5 X 4 = 20
5 X 5 = 25
5 X 6 = 30
5 X 7 = 35
5 X 8 = 40
5 X 9 = 45
5 X 10 = 50
改进或修复代码?代码是有效的,我得到了我想要的,但它不在表中,我得到了垂直的结果。我希望它在一个表中。您的代码有缩进问题。对不起,请把它们修好。我从IDE复制,缩进被弄乱了。我假设您使用的是Python 3.x?谢谢您的回答,这似乎很好,但我希望它是一个表,例如,像一个矩阵或一个棋盘,比如这样:谢谢,这就是我想要的!另外,非常感谢您提供的参考资料,我想问您在哪里可以了解有关格式的更多信息。@user2357既然您说您正在学习,我想它会对您有所帮助:)
1 tables
1 X 1 = 1
1 X 2 = 2
1 X 3 = 3
1 X 4 = 4
1 X 5 = 5
1 X 6 = 6
1 X 7 = 7
1 X 8 = 8
1 X 9 = 9
1 X 10 = 10
2 tables
2 X 1 = 2
2 X 2 = 4
2 X 3 = 6
2 X 4 = 8
2 X 5 = 10
2 X 6 = 12
2 X 7 = 14
2 X 8 = 16
2 X 9 = 18
2 X 10 = 20
3 tables
3 X 1 = 3
3 X 2 = 6
3 X 3 = 9
3 X 4 = 12
3 X 5 = 15
3 X 6 = 18
3 X 7 = 21
3 X 8 = 24
3 X 9 = 27
3 X 10 = 30
4 tables
4 X 1 = 4
4 X 2 = 8
4 X 3 = 12
4 X 4 = 16
4 X 5 = 20
4 X 6 = 24
4 X 7 = 28
4 X 8 = 32
4 X 9 = 36
4 X 10 = 40
5 tables
5 X 1 = 5
5 X 2 = 10
5 X 3 = 15
5 X 4 = 20
5 X 5 = 25
5 X 6 = 30
5 X 7 = 35
5 X 8 = 40
5 X 9 = 45
5 X 10 = 50