Python 使用scrapy从静态贴图获取lat lon

我正在尝试使用Scrapy从嵌入在网站上的静态地图中获取坐标（lat，lon）。当我检查元素时，我发现坐标正确 ，但我不知道如何得到它

我使用了

response.xpath（'//img[@id=“static map”]/@src'）.extract（）

我得到

'//maps.google.com/maps/api/staticmap?center=-12.119641500000000,-77.011014800000000&zoom=16&markers=-12.119641500000000,-77.011014800000000&key=AIzaSyB42QzVvI4Fz1sQMlJBHemUlH5zYH0VMIE&size=780x456&sensor=true&scale=2&signature=dl39BZVBkcNsfHm0FjeNzKw1puU='

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我想在两个不同的列中得到lat和lon（-12.11964，-77.011014）

通过XPath，您可以使用子字符串函数（和*1来删除结尾的零）：

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使用XPath，您可以使用子字符串函数（和*1来删除结尾的零）：

您可以解析url

import urllib.parse

url = '//maps.google.com/maps/api/staticmap?center=-12.119641500000000,-77.011014800000000&zoom=16&markers=-12.119641500000000,-77.011014800000000&key=AIzaSyB42QzVvI4Fz1sQMlJBHemUlH5zYH0VMIE&size=780x456&sensor=true&scale=2&signature=dl39BZVBkcNsfHm0FjeNzKw1puU='

query = urllib.parse.urlsplit(url).query
data = urllib.parse.parse_qs(query)
lat, lon = eval(data['center'][0])
print(lat, lon)

或者您可以将其视为普通文本并

split（）

url = '//maps.google.com/maps/api/staticmap?center=-12.119641500000000,-77.011014800000000&zoom=16&markers=-12.119641500000000,-77.011014800000000&key=AIzaSyB42QzVvI4Fz1sQMlJBHemUlH5zYH0VMIE&size=780x456&sensor=true&scale=2&signature=dl39BZVBkcNsfHm0FjeNzKw1puU='

lat, lon = eval(url.split("center=")[1].split('&')[0])
print(lat, lon)

您可以解析url

import urllib.parse

url = '//maps.google.com/maps/api/staticmap?center=-12.119641500000000,-77.011014800000000&zoom=16&markers=-12.119641500000000,-77.011014800000000&key=AIzaSyB42QzVvI4Fz1sQMlJBHemUlH5zYH0VMIE&size=780x456&sensor=true&scale=2&signature=dl39BZVBkcNsfHm0FjeNzKw1puU='

query = urllib.parse.urlsplit(url).query
data = urllib.parse.parse_qs(query)
lat, lon = eval(data['center'][0])
print(lat, lon)

或者您可以将其视为普通文本并

split（）

url = '//maps.google.com/maps/api/staticmap?center=-12.119641500000000,-77.011014800000000&zoom=16&markers=-12.119641500000000,-77.011014800000000&key=AIzaSyB42QzVvI4Fz1sQMlJBHemUlH5zYH0VMIE&size=780x456&sensor=true&scale=2&signature=dl39BZVBkcNsfHm0FjeNzKw1puU='

lat, lon = eval(url.split("center=")[1].split('&')[0])
print(lat, lon)