Python 错误:没有这样的列
我想用flask创建一个网站,它有一个带有链接的表,用户用html表单将链接放在那里Python 错误:没有这样的列,python,sqlite,flask,Python,Sqlite,Flask,我想用flask创建一个网站,它有一个带有链接的表,用户用html表单将链接放在那里 from flask import Flask, render_template, request, redirect from flask_sqlalchemy import SQLAlchemy from datetime import datetime app = Flask(__name__) app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///hom
from flask import Flask, render_template, request, redirect
from flask_sqlalchemy import SQLAlchemy
from datetime import datetime
app = Flask(__name__)
app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///home.db'
db = SQLAlchemy(app)
class links(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(30), nullable=True)
title = db.Column(db.String(30), nullable=False)
link = db.Column(db.String(200), nullable=False)
date_added = db.Column(db.DateTime, nullable=False, default=datetime.utcnow)
def __repr__(self):
return f'<link {self.id}>'
@app.route('/home', methods=['GET', 'POST'])
def home ():
if request.method == 'POST':
link_name = request.form["name"]
link_title = request.form["title"]
link_link = request.form["link"]
new_link = links(name=link_name, title=link_title, link=link_link)
try:
db.session.add(new_link)
db.session.commit()
return redirect('/home')
except:
return 'there was a problem'
else:
li = links.query.order_by(links.date_added).all()
return render_template('home.html', li=li)
if __name__ == "__main__":
app.run(debug=True)
我在网上做了一些研究,但没有发现任何东西。。。
如何修复此问题?如果您在项目目录中看到,但没有看到“home.db”文件,那么看起来您确实没有创建sqlite文件 然后打开python终端并执行以下操作:
>>> from app import db
>>> db.create_all()
>>> exit() #or ctrl + z then enter
app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///home.db'
>对此:
导入操作系统
app = Flask(__name__)
basedir = os.path.abspath(os.path.dirname(__file__))
app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///'+os.path.join(basedir, 'data.sqlite')
然后运行代码。另外,请记住,每次进行更改时都要删除文件“home.db”如果您在项目目录中看到的是“home.db”文件,而不是它,那么看起来您确实没有创建sqlite文件 然后打开python终端并执行以下操作:
>>> from app import db
>>> db.create_all()
>>> exit() #or ctrl + z then enter
app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///home.db'
>对此:
导入操作系统
app = Flask(__name__)
basedir = os.path.abspath(os.path.dirname(__file__))
app.config['SQLALCHEMY_DATABASE_URI'] = 'sqlite:///'+os.path.join(basedir, 'data.sqlite')
然后运行代码。还记得每次更改时都要删除文件“home.db”检查我的答案检查我的答案