Python 从其他两个字典中创建一个相似的字典
我有两本这样的字典:Python 从其他两个字典中创建一个相似的字典,python,dictionary,Python,Dictionary,我有两本这样的字典: dict1= {'MO': ['N-2', 'N-8', 'N-7', 'N-6', 'N-9'], 'MO2': ['N0-6'], 'MO3': ['N-2']} dict2= {'N-2': ['NUMBER1'], 'N0-6': ['NUMBER16'], 'N-9': ['NUMBER33'] 我想创建一本这样的词典 dict3={'MO'['NUMBER1','NUMBER33'], 'MO2':['NUMBER16']} 所以我开发了这段代码,但是当我添
dict1= {'MO': ['N-2', 'N-8', 'N-7', 'N-6', 'N-9'], 'MO2': ['N0-6'], 'MO3': ['N-2']}
dict2= {'N-2': ['NUMBER1'], 'N0-6': ['NUMBER16'], 'N-9': ['NUMBER33']
我想创建一本这样的词典
dict3={'MO'['NUMBER1','NUMBER33'], 'MO2':['NUMBER16']}
所以我开发了这段代码,但是当我添加值时,它不起作用
for ki, vi in dict2.items():
for key, value in (itertools.chain.from_iterable([itertools.product((k, ), v) for k, v in dict3.items()])):
if (ki == v):
print vi
用defatuldict试试这个
from collections import defaultdict
d =defaultdict(list)
for k in dict1.keys():
for value in dict1[k]:
temp = dict2.get(value)
if temp:
d[k].append(temp)
输出
defaultdict(list,
{'MO': [['NUMBER1'], ['NUMBER33']],
'MO2': [['NUMBER16']],
'MO3': [['NUMBER1']]})
您只需循环使用其中一个字典:
dict1= {'MO': ['N-2', 'N-8', 'N-7', 'N-6', 'N-9'], 'MO2': ['N0-6'], 'MO3': ['N-2']}
dict2= {'N-2': ['NUMBER1'], 'N0-6': ['NUMBER16'], 'N-9': ['NUMBER33']}
dict3 = {}
for key, subkeys in dict1.items():
for subkey in subkeys:
dict3.setdefault(key, []).extend(dict2.get(subkey, []))
一行D
{k: [y for x in xs if x in d2 for y in d2[x]] for k, xs in d1.items()}
d1
中的每个键(k
)和值(xs
)xs
中的每个项目x
,如果d2
包含x
,我们会找到通过d2
的路径y。。。对于d2中的y[x]
{
k: [
y
for x in xs if x in d2
for y in d2[x]
]
for k, xs in d1.items()
}