Python 调用文本，但完全排除表

我正在使用Beautiful Soup加载XMl。我所需要的只是文本，忽略标记和

text

属性词

但是，我想完全排除

标记中的任何内容。我曾想过用正则表达式来代替中间的所有东西，但我想知道是否有更干净的解决方案，部分原因是。例如：

s =""" <content><p>Hasselt ( ) is a <link target="Belgium">Belgian</link> <link target="city">city</link> and <link target="Municipalities in Belgium">municipality</link>. 
<table><cell>Passenger growth
<cell>Year</cell><cell>Passengers</cell><cell>Percentage </cell></cell>
<cell>1996</cell><cell>360 000</cell><cell>100%</cell>
<cell>1997</cell><cell>1 498 088</cell><cell>428%</cell>
</table>"""
clean = Soup(s)
print clean.text

而我只想：

Hasselt ( ) is a Belgian city and municipality.

---

您可以找到

内容

元素并从中删除所有

表

元素，然后获取文本：

from bs4 import BeautifulSoup

s =""" <content><p>Hasselt ( ) is a <link target="Belgium">Belgian</link> <link target="city">city</link> and <link target="Municipalities in Belgium">municipality</link>.
<table><cell>Passenger growth
<cell>Year</cell><cell>Passengers</cell><cell>Percentage </cell></cell>
<cell>1996</cell><cell>360 000</cell><cell>100%</cell>
<cell>1997</cell><cell>1 498 088</cell><cell>428%</cell>
</table>"""
soup = BeautifulSoup(s, "xml")

content = soup.content
for table in content("table"):
    table.extract()

print(content.get_text().strip())

---

你一定是在问题的墨汁干之前就开始写代码的；）@事实上，我们已经准备好了

bs4

方便的代码片段。我们在这里做严肃的运动！谢谢

from bs4 import BeautifulSoup

s =""" <content><p>Hasselt ( ) is a <link target="Belgium">Belgian</link> <link target="city">city</link> and <link target="Municipalities in Belgium">municipality</link>.
<table><cell>Passenger growth
<cell>Year</cell><cell>Passengers</cell><cell>Percentage </cell></cell>
<cell>1996</cell><cell>360 000</cell><cell>100%</cell>
<cell>1997</cell><cell>1 498 088</cell><cell>428%</cell>
</table>"""
soup = BeautifulSoup(s, "xml")

content = soup.content
for table in content("table"):
    table.extract()

print(content.get_text().strip())

Hasselt ( ) is a Belgian city and municipality.