Python 无双for循环展平numpy阵列
我有一个二维矩阵。在本例中,假设它是一个随机矩阵Python 无双for循环展平numpy阵列,python,numpy,Python,Numpy,我有一个二维矩阵。在本例中,假设它是一个随机矩阵 >>> a = np.random.randn(5, 7) >>> a array([[-0.37279322, 0.28619523, -0.05309901, 0.26010327, 0.1846693 , 0.33112176, 0.75814911], [ 1.57001151, -0.86831693, -0.20576395, 1.46450855, -0.01631132,
>>> a = np.random.randn(5, 7)
>>> a
array([[-0.37279322, 0.28619523, -0.05309901, 0.26010327, 0.1846693 , 0.33112176, 0.75814911],
[ 1.57001151, -0.86831693, -0.20576395, 1.46450855, -0.01631132, 3.02790403, -0.65313017],
[ 0.2362675 , -1.52190536, 0.04687194, 2.01618876, 0.03780218, -0.53041096, -0.30104844],
[-0.5504834 , 1.04286156, 1.12863785, 0.89583492, 0.28607363, 1.42858007, 0.28582572],
[-0.768464 , 0.31952554, 0.81129581, 0.26239668, -0.23242878, -1.01584339, 0.39573906]])
和两个标签向量:
label_y = np.array([23, 984, 123, 9321, 121238])
label_x = np.array([121, 31312, 9123131, 1111, 1231441, 1929313, 192312312361])
我想将a的元素展平并输出它们的标签索引和值。例如:
23,121,-0.37279322
23,31312,0.28619523
23,9123131,-0.05309901
23,1111,0.26010327
23,1231441,0.1846693
23,1929313,0.33112176
23,192312312361,0.75814911
984,121,...
...
在numpy中有没有一种不使用for循环的简单方法?用于创建与X
和Y
标签对应的2D
网格,然后将它们与2D
输入数组a
一起堆叠为列,如下所示-
X,Y = np.meshgrid(label_x,label_y)
out = np.column_stack((Y.ravel(),X.ravel(),a.ravel()))
用于创建对应于X
和Y
标签的2D
网格,然后将其作为列与2D
输入数组a
一起堆叠,如下所示-
X,Y = np.meshgrid(label_x,label_y)
out = np.column_stack((Y.ravel(),X.ravel(),a.ravel()))