在Python中比较字典的键并提取相应的值
我有两本字典:-在Python中比较字典的键并提取相应的值,python,dataframe,dictionary,Python,Dataframe,Dictionary,我有两本字典:- dict_1 = {'a': ["['b','c','d','e']"],'b': ["['a','c','d','e']"],'p': ["['q','r','s']"]} dict_2 = {'a': ["['x','y','z','n']"],'b': ["['u','v','w','x','y','z','n']"]} 我想提取两个字典中存在的所有键的值,这样在同一时刻,我只能从字典中获取对应键的一个值 dict_1 = {'a': ["['b','c',
dict_1 = {'a': ["['b','c','d','e']"],'b': ["['a','c','d','e']"],'p': ["['q','r','s']"]}
dict_2 = {'a': ["['x','y','z','n']"],'b': ["['u','v','w','x','y','z','n']"]}
我想提取两个字典中存在的所有键的值,这样在同一时刻,我只能从字典中获取对应键的一个值
dict_1 = {'a': ["['b','c','d','e']"],'b': ["['a','c','d','e']"],'p': ["['q','r','s']"]}
dict_2 = {'a': ["['x','y','z','n']"],'b': ["['u','v','w','x','y','z','n']"]}
预期产出
dict_1 = {'a': ["['b','c','d','e']"],'b': ["['a','c','d','e']"],'p': ["['q','r','s']"]}
dict_2 = {'a': ["['x','y','z','n']"],'b': ["['u','v','w','x','y','z','n']"]}
dict_1 = {'a': ["['b','c','d','e']"],'b': ["['a','c','d','e']"],'p': ["['q','r','s']"]}
dict_2 = {'a': ["['x','y','z','n']"],'b': ["['u','v','w','x','y','z','n']"]}
请帮助我获取输出。我将假设此输入:
dict_1 = {'a': ["['b','c','d','e']"],'b': ["['a','c','d','e']"],'p': ["['q','r','s']"]}
dict_2 = {'a': ["['x','y','z','n']"],'b': ["['u','v','w','x','y','z','n']"]}
dict_1 = {'a': ['b','c','d','e'],'b': ['a','c','d','e'],'p': ['q','r','s']}
dict_2 = {'a': ['x','y','z','n'],'b': ['u','v','w','x','y','z','n']}
如果没有,您可以使用dict_i={k:literal_eval(v)for k,v in dict_i.items()}
dict_1 = {'a': ["['b','c','d','e']"],'b': ["['a','c','d','e']"],'p': ["['q','r','s']"]}
dict_2 = {'a': ["['x','y','z','n']"],'b': ["['u','v','w','x','y','z','n']"]}
您可以使用理解来选择期望的数据,并使用它来构建数据框架:
dict_1 = {'a': ["['b','c','d','e']"],'b': ["['a','c','d','e']"],'p': ["['q','r','s']"]}
dict_2 = {'a': ["['x','y','z','n']"],'b': ["['u','v','w','x','y','z','n']"]}
data = [(k, v1, v2) for k in dict_1 if k in dict_2
for v1, v2 in zip(dict_1[k], dict_2[k])]
df = pd.DataFrame(data)
它给出:
dict_1 = {'a': ["['b','c','d','e']"],'b': ["['a','c','d','e']"],'p': ["['q','r','s']"]}
dict_2 = {'a': ["['x','y','z','n']"],'b': ["['u','v','w','x','y','z','n']"]}
0 1 2
0 a b x
1 a c y
2 a d z
3 a e n
4 b a u
5 b c v
6 b d w
7 b e x
我不知道什么是数据帧。以下是代码和示例输出:
dict_1 = {'a': ["['b','c','d','e']"],'b': ["['a','c','d','e']"],'p': ["['q','r','s']"]}
dict_2 = {'a': ["['x','y','z','n']"],'b': ["['u','v','w','x','y','z','n']"]}
dict_one = {1: [1, 2, 3, 4]}
dict_two = {1: [7, 8, 9, 10]}
all_keys = set(dict_one).union(set(dict_two))
rows = []
for key in all_keys:
dict_one_values = []
if key in dict_one:
dict_one_values = dict_one[key]
dict_two_values = []
if key in dict_two:
dict_two_values = dict_two[key]
for i in range(min(len(dict_one_values), len(dict_two_values))):
rows.append([key, dict_one_values[i], dict_two_values[i]])
for row in rows:
print(*row)
输出:
dict_1 = {'a': ["['b','c','d','e']"],'b': ["['a','c','d','e']"],'p': ["['q','r','s']"]}
dict_2 = {'a': ["['x','y','z','n']"],'b': ["['u','v','w','x','y','z','n']"]}
1 1 7
1 2 8
1 3 9
1 4 10
收集数据的方法是什么?请给出几个简单的例子。为什么
'a':[“['b','c','d','e']
而不是“a':['b','c','d','e']
?