Python numba@vectorize target=&x27;平行';打字错误
如果我定义Python numba@vectorize target=&x27;平行';打字错误,python,numba,Python,Numba,如果我定义 import numba as nb import numpy as np @nb.vectorize def nb_vec(x): if x>0: x=x+100 return x 然后 顺利运行 但是如果我添加目标选项,比如 @nb.vectorize(target='parallel') def nb_vec(x): if x>0: x=x+100 return x 然后 输出错误消息 ------
import numba as nb
import numpy as np
@nb.vectorize
def nb_vec(x):
if x>0:
x=x+100
return x
然后
顺利运行
但是如果我添加目标选项,比如
@nb.vectorize(target='parallel')
def nb_vec(x):
if x>0:
x=x+100
return x
然后
输出错误消息
---------------------------------------------------------------------------TypeError回溯(最近的调用
最后)在
1 x=np.随机。随机(1000000)
---->2 nb_vec(x)
TypeError:输入类型不支持ufunc'nb_vec',并且
根据,无法将输入安全地强制为任何受支持的类型
铸造规则“安全”
有什么问题吗?在numba 0.46中,无签名的
numba.vectorize
decorator将创建一个动态通用函数,这意味着它在调用时根据类型编译代码。所以你不需要提供签名
import numpy as np
import numba as nb
@nb.vectorize()
def nb_vec(x):
if x > 0:
x = x + 100
return x
>>> nb_vec
<numba._DUFunc 'nb_vec'>
>>> nb_vec.types
[]
>>> nb_vec(np.ones(5))
array([101., 101., 101., 101., 101.])
>>> nb_vec.types
['d->d']
这里的解决方案是在使用并行矢量化时指定具有适当类型的签名:
import numpy as np
import numba as nb
@nb.vectorize(
[nb.int32(nb.int32),
nb.int64(nb.int64),
nb.float32(nb.float32),
nb.float64(nb.float64)],
target='parallel')
def nb_vec(x):
if x > 0:
x = x + 100
return x
import numpy as np
import numba as nb
@nb.vectorize()
def nb_vec(x):
if x > 0:
x = x + 100
return x
>>> nb_vec
<numba._DUFunc 'nb_vec'>
>>> nb_vec.types
[]
>>> nb_vec(np.ones(5))
array([101., 101., 101., 101., 101.])
>>> nb_vec.types
['d->d']
import numpy as np
import numba as nb
@nb.vectorize(target='parallel')
def nb_vec(x):
if x > 0:
x = x + 100
return x
>>> nb_vec
<ufunc 'nb_vec'>
>>> nb_vec.types
[]
import numpy as np
import numba as nb
@nb.vectorize(
[nb.int32(nb.int32),
nb.int64(nb.int64),
nb.float32(nb.float32),
nb.float64(nb.float64)],
target='parallel')
def nb_vec(x):
if x > 0:
x = x + 100
return x