Python 无法从剪贴画中提取图像链接

我正在使用scrapy从网站中提取产品的图像链接，但返回的输出是一个空列表，我尝试了所有组合，请帮助 '''

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我认为这可能与网站政策有关。 下面的代码非常适合这个网站

url = "http://hdresim.net/"
source = requests.get(url).text

soup = BeautifulSoup(source, "lxml")
main = soup.find("div", attrs={"class":'icerik'})
for i in main.findAll("img"):
  print(i["src"])

结果如下：

http://hdresim.net/resimler/r6/k_karinca(10).jpg
http://hdresim.net/resimler/r3/k_deniz_canlilari(38).jpg
http://hdresim.net/resimler/r5/k_sonbahar14(44).jpg
http://hdresim.net/resimler/r7/k_yaz16(3).jpg
..

但当我尝试同样的方法来访问你们的站点时，我会得到一个空列表

url = "https://www.flipkart.com/clothing-and-accessories/topwear/pr?sid=clo%2Cash&otracker=categorytree&p%5B%5D=facets.ideal_for%255B%255D%3DMen"
source = requests.get(url).text
soup = BeautifulSoup(source, "lxml")

main = soup.findAll("div", attrs={"class":"_13oc-S"})

for images in  soup.findAll("img", attrs={"class":"_2r_T1I"}):
  print(images["src"])

url = "https://www.flipkart.com/clothing-and-accessories/topwear/pr?sid=clo%2Cash&otracker=categorytree&p%5B%5D=facets.ideal_for%255B%255D%3DMen"
source = requests.get(url).text
soup = BeautifulSoup(source, "lxml")

main = soup.findAll("div", attrs={"class":"_13oc-S"})

for images in  soup.findAll("img", attrs={"class":"_2r_T1I"}):
  print(images["src"])