如何使用python从数据结构中提取字典？

这是一个名为grade_list的表格，它将学生的名字映射到他们考试成绩的列表中。等级应从字符串转换为整数。例如，grade_列出了['Thorny']=[100,90,80]。有人能帮我吗

 grades = [ #here is the table
    ['Student', 'Exam 1', 'Exam 2', 'Exam 3'],
    ['Thorny', '100', '90', '80'],
    ['Mac', '88', '99', '111'],
    ['Farva', '45', '56', '67'],
    ['Rabbit', '59', '61', '67'],
    ['Ursula', '73', '79', '83'],
    ['Foster', '89', '97', '101']
]

---

只需使用

dict

遍历列表即可：

grades_dict = dict((x[0],x[1:]) for x in grades[1:])
grades_dict

输出：

{'Farva': ['45', '56', '67'],
 'Foster': ['89', '97', '101'],
 'Mac': ['88', '99', '111'],
 'Rabbit': ['59', '61', '67'],
 'Thorny': ['100', '90', '80'],
 'Ursula': ['73', '79', '83']}

和

等级[棘手的]

：

['100', '90', '80']

---

使用将值映射到整数的字典理解：

{x[0]: list(map(int, x[1:])) for x in grades[1:]}

示例：

grades = [ #here is the table
    ['Student', 'Exam 1', 'Exam 2', 'Exam 3'],
    ['Thorny', '100', '90', '80'],
    ['Mac', '88', '99', '111'],
    ['Farva', '45', '56', '67'],
    ['Rabbit', '59', '61', '67'],
    ['Ursula', '73', '79', '83'],
    ['Foster', '89', '97', '101']
]

print({x[0]: list(map(int, x[1:])) for x in grades[1:]})

# {'Thorny': [100, 90, 80], 
#  'Mac': [88, 99, 111],
#  'Farva': [45, 56, 67],
#  'Rabbit': [59, 61, 67],
#  'Ursula': [73, 79, 83],
#  'Foster': [89, 97, 101]}

---

这将输出一个字典，名称作为键，标记列表将每个标记转换为整数作为键的值。

只需运行这段代码

grades = [ #here is the table
    ['Student', 'Exam 1', 'Exam 2', 'Exam 3'],
    ['Thorny', '100', '90', '80'],
    ['Mac', '88', '99', '111'],
    ['Farva', '45', '56', '67'],
    ['Rabbit', '59', '61', '67'],
    ['Ursula', '73', '79', '83'],
    ['Foster', '89', '97', '101']
]
dict = {}
for student_data in grades:
   if student_data[0] == "Student":
     continue
   else:
     temp_list = []
     temp_list.append(int(student_data[1]))
     temp_list.append(int(student_data[2]))
     temp_list.append(int(student_data[3]))
     dict[student_data[0]] = temp_list

print(dict)

---

针对上述问题的简单一行程序：

---

grades\u dict=dict（map（lambda x:（x[0]，x[1:），grades））

您可以直接使用字典理解，而不是迭代列表，然后将其转换为字典。更像是蟒蛇

grades = [ #here is the table
    ['Student', 'Exam_1', 'Exam_2', 'Exam_3'],
    ['Thorny', '100', '90', '80'],
    ['Mac', '88', '99', '111'],
    ['Farva', '45', '56', '67'],
    ['Rabbit', '59', '61', '67'],
    ['Ursula', '73', '79', '83'],
    ['Foster', '89', '97', '101']
]
grade = {g[0]:g[1:] for g in grades[1:]}
print(grade)

# Output
#{'Thorny': ['100', '90', '80'], 'Mac': ['88', '99', '111'], 'Ursula': ['73', '79', '83'], 'Farva': ['45', '56', '67'], 'Foster': ['89', '97', '101'], 'Rabbit': ['59', '61', '67']}

---

你能分享一下你到目前为止所做的尝试吗？你添加了三次

student\u数据[1]

。这将产生错误的输出刚刚修复。谢谢