Python 提取html的特定部分
我正在使用html请求和BeautifulSoup开发一个webscraper(这是新的)。对于1个网页(),我正在尝试刮取一个部件,我将为其他产品复制该部件。html看起来像:Python 提取html的特定部分,python,html,web-scraping,beautifulsoup,python-requests-html,Python,Html,Web Scraping,Beautifulsoup,Python Requests Html,我正在使用html请求和BeautifulSoup开发一个webscraper(这是新的)。对于1个网页(),我正在尝试刮取一个部件,我将为其他产品复制该部件。html看起来像: <div class="plp-listing-load-status c-list-header__counter initialized" data-page-number="1" data-total-pages-count="57" data-p
<div class="plp-listing-load-status c-list-header__counter initialized" data-page-number="1" data-total-pages-count="57" data-products-count="60" data-total-products-count="3361" data-status-format="{available}/{total} results">60/3361 results</div>
及
但两者都返回
None
。我不知道如何具体选择57。任何帮助都将被告知要获取总页数,您可以使用以下示例:
import requests
from bs4 import BeautifulSoup
url = "https://www.selfridges.com/GB/en/cat/beauty/make-up/?pn=1"
headers = {
"User-Agent": "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:87.0) Gecko/20100101 Firefox/87.0"
}
soup = BeautifulSoup(requests.get(url, headers=headers).text, "html.parser")
print(soup.select_one("[data-total-pages-count]")["data-total-pages-count"])
印刷品:
56
import requests
from bs4 import BeautifulSoup
url = "https://www.selfridges.com/GB/en/cat/beauty/make-up/?pn=1"
headers = {
"User-Agent": "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:87.0) Gecko/20100101 Firefox/87.0"
}
soup = BeautifulSoup(requests.get(url, headers=headers).text, "html.parser")
print(soup.select_one("[data-total-pages-count]")["data-total-pages-count"])
56