查找python文本中是否存在单词的逻辑

我有一个字符串和一个单词列表，我想检查它们是否存在于给定的文本字符串中。我正在使用以下逻辑…是否有其他方法来优化它：-

import re
text="""
Python is an interpreted, object-oriented, high-level programming language with dynamic semantics.
Its high-level built in data structures, combined with dynamic typing and dynamic binding, make
it very attractive for Rapid Application Development"""
tokens_text=re.split(" ",text)
list_words=["programming","Application"]
if (len(set(list_words).intersection(set(tokens_text)))==len(list_words)):
    print("Match_Found")

操作：

text="""
Python is an interpreted, object-oriented, high-level programming language with dynamic semantics.
Its high-level built in data structures, combined with dynamic typing and dynamic binding, make
it very attractive for Rapid Application Development"""
tokens = text.split()
list_words = ["programming", "Application"]

if (set(list_words).issubset(set(tokens))):
    print("Match_Found")

或者只需使用

all

功能：

if all(x in tokens for x in list_words):
    print("Match_Found")

---

您可以使用python的in操作符，我不知道它是否更快

str = "Messi is the best soccer player"

"soccer" in str
-> True

"football" in str
-> False

---

这将需要更多的时间，因为它将在for循环中的每一个元素。而且我想检查一下，如果列表中的这两个词都出现在文本中。我认为在这种情况下它不会有帮助……是的，你也应该循环搜索字符串，祝你好运：）