Python 在列表列表中展平内部列表

假设我有以下对象列表：

lol = [['When was America discovered by Christopher Colombus?', ['1492', '1510', '1776', '1820'], '1492'], ['What is the name of the school that Harry Potter attends?', ['Hogwarts', 'Gryffindor', 'Voldemort', 'Magic School'], 'Hogwarts'], ['How many colors are there in the common depiction of the rainbow?', ['5', '7', '9', '11'], '7']

我正在尝试将内部列表展平（例如，删除括号）。结果看起来像

['When was America discovered by Christopher Colombus?', '1492', '1510', '1776', '1820', '1492']

我已经看到了整平整个列表的一般解决方案，如下所示：

---

但我不知道如何在一个更大的列表中选择性地展平一个列表

如果你知道如何展平整个列表，并且你想知道如何仅展平第一个列表，那么你不是在问如何展平列表，而是在问如何选择列表中的第一项，答案是执行

sublist=lol[0]

，然后将其他问题的答案应用到

sublist

我认为您的意思是，您不仅需要显示的输出，还需要示例输出中的其他两个。以下是如何做到这一点：

lol = [['When was America discovered by Christopher Colombus?', ['1492', '1510', '1776', '1820'], '1492'], ['What is the name of the school that Harry Potter attends?', ['Hogwarts', 'Gryffindor', 'Voldemort', 'Magic School'], 'Hogwarts'], ['How many colors are there in the common depiction of the rainbow?', ['5', '7', '9', '11'], '7']]

r = []
for x in lol:
    r.append([x[0]] + x[1] + [x[2]])

for rr in r:
    print(rr)

结果:

['When was America discovered by Christopher Colombus?', '1492', '1510', '1776', '1820', '1492']
['What is the name of the school that Harry Potter attends?', 'Hogwarts', 'Gryffindor', 'Voldemort', 'Magic School', 'Hogwarts']
['How many colors are there in the common depiction of the rainbow?', '5', '7', '9', '11', '7']